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if we have 75, four-hundred pound men, sitting in a bus which is traveling at 168 miles per hour down the hi-way.... what is the average speed of this bus, if after 20 miles, these large men begin yodeling, pissing off the bus driver, thus slowing the bus to 98 miles per hour for 3 minutes...
during this time, the bus driver will tell these large yodelers to cease their yodeling... then the bus driver will increase the speed of the bus back to the original 168 miles per hour... so what is the average speed of this bus after 60 minutes???

2006-11-24 03:17:58 · 3 answers · asked by bigschwinger 2 in Science & Mathematics Physics

3 answers

t1=s1/v is time before yodeling, s1=20 miles, v=168mph; s2=t2*v2 is path of yodeling, t2=3/60 hours, v2=98mph; s3=t3*v is path of the bus after yodeling, t=t1+t2+t3=1 hour or t3=t-t1-t2, s=s1+s2+s3 is total path of silent+yodeling+shut_up phenomena; thus u=s/t is average speed of the bus;
u=(20 + (3/60)*98 + (1-20/168-3/60)*168) / 1=
=164.5mph

2006-11-24 05:35:56 · answer #1 · answered by Anonymous · 0 0

Um, well, after the last time the bus driver turned around to tell them all to shut it, he drove off a cliff, so my answer is it fell at a rate of 200mph with a sudden stop at the bottom.

2006-11-24 03:27:22 · answer #2 · answered by dreamer 3 · 0 0

ok i don't get the question, but that is a very fast bus!

2006-11-24 03:28:53 · answer #3 · answered by vball_chik 2 · 0 0

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