3x+7y=3
7y=-3x+3
y=-3/7*x+3/7
Slope=-3/7
We have the slope and point[-6,7]
We will find the intercept
7=-3/7*-6+c
c=7-18/7
=[49-18]/7
=31/7
We now have the slope and intercept
The equation is
y=-3/7*x+31/7
7y+3x-31=0
2006-11-24 03:11:38
·
answer #1
·
answered by openpsychy 6
·
1⤊
0⤋
Slope-intercept variety ability you ought to locate the slope and intercept first. From the equation given bellow because the line that go by (3,a million) is parallel to y= -3x+6. Then which ability they have a similar slope it really is a similar as -3 replace this slope and the point given contained in the overall equation of a instantly line to acquire intercept C, Y = Mx + C the position M is the gradient. At (3,a million) a million = -3(3) + C a million =-9 + C C =a million + 9 = 10. :.y =mx + c. placed m and c purely contained in the above equation then the equation of the line that bypass throug (3,a million) is: y = -3x +10.
2016-11-29 10:25:25
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
You have one line 3x + 7y = 3.
You can write this line in the form y = (-3/7)x + (3/7)
So, this is a line with slope m=(-3/7).
The line you would like to find is parallel to above line, so the required line will also have the same slope m=(-3/7).
Let the required line be y = mx + c.
With availabel slope you can write y = (-3/7)x + c.
Also, we know that thi line passes through (-6,7),
Thus we have 7 = (-3/7)(-6) + c
=>7 = (1/14) + c
=>c = 7-(1/14)
=>c = 97/14
Thus, the required line is
y = (-3/7)x + (97/14)
or
14y + 6x = 97
I hope i answered your question.
All the best.
2006-11-24 03:13:32
·
answer #3
·
answered by Paritosh Vasava 3
·
1⤊
0⤋
Here is a way to solve it.
given equation is 3x+7y=3
any line parallel to above line is 3x+7y+k=0
putting (-6,7)in above equation, we get,
3*-6+7*7+k=0
k= -31
ie; the equation is 3x+7y=31
or, 3x/31+7y/31=0
or, x/(31/3)+y(31/7)=0
ie:- x intercept = 31/3
y intercept = 31/7
here u go
2006-11-24 03:12:58
·
answer #4
·
answered by Ankit B 4
·
0⤊
0⤋
let y = ax+b
the line parallel to 3x+7y = 3 or y = -3/7 x +3/7
The line we search is of the form y = -3/7 x +b
you replace (-6,7) to find b
7 =-(3/7) * -6 +b
b = 7 -18/7 = 31/7
2006-11-24 03:18:05
·
answer #5
·
answered by maussy 7
·
0⤊
0⤋
3x+7y=3
7y=3-3x
y=(3/7)-(3x/7) ==> A instead of 3/7 and (-6,7) instead of (x,y)
7=A+(18/7)
so: PARALLEL LINE Y=(31/7)-(3X/7)
good luck
2006-11-24 03:23:11
·
answer #6
·
answered by yuri Romanov 2
·
0⤊
0⤋
y=-x+1
take two points on the equation 3x+7y=3,then from the given point (-6,7) by doing togeter you can get your answer.
2006-11-24 03:45:42
·
answer #7
·
answered by milion t 1
·
0⤊
0⤋
equation of lineparallel to 3x+7y=3
will be 3x+7y+k=0
passes through((-6,7)
-18+49+k=0
k=-31
so the equation=3x+7y-31=0
7y=-3x+31
y=(-7/3)x+(31/7)
2006-11-24 03:39:30
·
answer #8
·
answered by raj 7
·
0⤊
0⤋
3x + 7y = 3
7y=-3x+3
y=-3x/7+3/7
slope=-3/7
7=-3/7(-6)+b
49=18+7b
7b=31
b=4 3/7
y=-3x/7+31/7
2006-11-24 05:23:34
·
answer #9
·
answered by yupchagee 7
·
0⤊
0⤋
y-7 / x+6 = -3/7
or y = (-3/7)x - 18/7 + 7
or y = (-3/7)x + 31/7
2006-11-24 03:22:38
·
answer #10
·
answered by ag_iitkgp 7
·
0⤊
0⤋