write the equation in slope-intercept form.through (-5,2);perpendicular to -5x-2y=27?

Question

college algebra

Answer 1

slope of -5x-2y=27 is -5/2
slope of perpendicular line=2/5
passes through(-5,2)
the equation
y-2=(2/5)(x+5)
5y-10=2x+10
2x-5y-20=0
in the slope interceptform
-5y=-2x+20
5y=2x-20
y=(2/5)x-4

Answer 2

This gives -2y = 5x+27 or y= -5/2 x - a' 13.5
The straight line perpendicular on this has if y=ax+b a slope a' such as aa' =-1 so à = 2/5

to find the intercept b' you must write that y = a' x +b' through (-5 ,2)

2 = 0.4 *-5 +b' and b' =4

the line is y = 2/5 x +4

Answer 3

You have one line -5x - 2y = 27.

You can write this line in the form y = (-27/5)x + (-2/5)

So, this is a line with slope m=(-27/5).

The line you would like to find is parallel to above line, so the required line will also have the same slope m=(-27/5).

Let the required line be y = mx + c.
With availabel slope you can write y = (-27/5)x + c.

Also, we know that thi line passes through (-5,2),
Thus we have 2 = (-27/5)(-5) + c
=>2 = 27 + c
=>c = -27+2
=>c = -25

Thus, the required line is
y = (-27/5)x + (-25)
or
5y + 27x = -125

I hope i answered your question.

Answer 4

First instruct the equation 5x+8y=a million for y. 5x+8y=a million 8y=a million -5x y= a million/8 -5/8x to locate the equation it extremely is perpendicular to the previous equation you're taking the reciprocal of -5/8 and alter the sign (8/5) to locate the slope. Then to locate b (the y-intercept) you employ the factors (10,12) and remedy for b. y= 8/5x +b 12= 8/5(10) +b 12=eighty/5 +b 12=sixteen +b -4=b The equation is y= 8/5x -4.

Answer 5

-5x-2y=27
2y=-5x-27
y=-5/2*x-27/2
Slope=-5/2
Let the slope of the required line be=m
m*-5/2=-1
m=2/5
Point=[-5,2]
We will find the intercept on y-axis
2=2/5*-5+c
c=2+2
=4
The required equation is
y=2/5*x+4

Answer 6

y-2 / x+5 = 2/5

or y = (2/5)x + 2 + 2

or y = (2/5)x + 4

Answer 7

-5x-2y=27
-2y=5x+27
y=-5x/2-27/2
slope=-5/2
slope of perpinduculat=2/4
y=2x/5+b
2=2/5(-5)+b
2=-2+b
b=4
y=2x/5+4