in the xy-coordinate plane, line L is perpendicular to the y-axis and passes through the points (5,-3) which of the following is an equation of line L?
the answer is y = -3 but I don't know how to solve it, could you please explain to me how you solve it step by step.
thanks in advance.
2006-11-24 02:12:25 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
since the line is perpendicular to y - axis . that means the x value can change but y value remains the same.
It is given that ( 5, -3) is a point on the line. So, y = (-3)
2006-11-24 02:22:27 · answer #1 · answered by Naval Architect 5 · 1⤊ 0⤋
lines that are perp to the y axis are horizontal lines... the equation is always of the form y = aconstant. In this case since you know that it goes through (5,-3) y = -3 for the entire line.
Another way is to use point slope and know that if a line is perp to the y axis it has a slope of 0
(y- - 3)=0(x-5) gives you y + 3= 0
so y = -3
2006-11-24 10:18:49 · answer #2 · answered by dla68 4 · 1⤊ 0⤋
hehe well whats the y intercept or slope ???????
2006-11-24 16:40:19 · answer #3 · answered by your pal 2 · 0⤊ 0⤋