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While watching boats going through the locks with some friends, you see a large, heavily laden barge loaded with steel about to be lowered. One friend says, "Hey, see where the water line is in the lock? If that barge were to sink for some reason right now, would the water level rise or fall or stay the same?" You craftily respond, "What do you think?" As she struggles with the thinking, it gives you an opportunity to think it to think it through yourself. What do you come up with?

2006-11-24 00:35:25 · 6 answers · asked by bluemiano 2 in Cars & Transportation Boats & Boating

6 answers

The water level in the lock is totally controlled. It would not change if the barge sank. If it sank quickly, there might be a momentary rise but then it would stay the same.

2006-11-24 01:41:26 · answer #1 · answered by science teacher 7 · 0 1

You didn't say if the barge was inside the lock or outside. If it was inside, and the lock was water tight. the level would rise to match whatever volume of metal it took to make the barge. If the barge is out side the lock then the same thing would happen except the rise would be so small that you couldn't measure it. For all pratical matters there would be no rise in the water level

2006-11-24 05:57:42 · answer #2 · answered by Anonymous · 0 1

actually, the water level would drop. If the barge sank, water that was displaced outside would fill the empty spaces inside, lowering the level by a relatively small amount. You can test this at home with a tub of water and a tea-cup.

2006-11-24 00:40:27 · answer #3 · answered by boots 6 · 2 0

I'm guessing the water level stays the same, because the weight of the floating barge is already displacing the same amount of water that would be displaced if the barge sank.

Not sure if I'm right, but that's my guess!

2006-11-24 00:37:56 · answer #4 · answered by Stretchy McSlapNuts 3 · 0 0

The water level would stay the same as it is controlled in the locks control room. It will stay at a consistent level no matter what the different displacement is applied to it.

2006-11-24 01:15:50 · answer #5 · answered by Doug 3 · 0 1

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2016-12-10 14:57:34 · answer #6 · answered by ? 4 · 0 0

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