2006-11-24 00:31:53 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This is works like n-2^(n-2)
1-1 = 1-2^(2-2) = 1-2^0 = 1-1
3-2 = 3-2^(3-2) = 3-2^1 = 3-2
5-8 = 5-2^(5-2) = 5-2^3 = 5-8
7-x = 7-2^(7-2) = 7-2^5 = 7-32
Thus x is 32.
2006-11-24 00:56:09 · answer #1 · answered by Paritosh Vasava 3 · 1⤊ 1⤋
What you're saying is that there is some function f such that
1 = f(1), 3 = f(2), 5 = f(8), 7 = f(x) so what value is x.
From the fundamental Theory of Algebra, there are an infinite number of polynomial functions that could be used as f so there is no unique x that makes 7 = f(x).
Use Legendres polynomial and let x = -1 or some such. It's what I usually do when someone hands me a silly question such as this.
Doug
2006-11-24 00:58:17 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
x=13
2006-11-24 00:33:39 · answer #3 · answered by raj 7 · 0⤊ 0⤋
12?
2006-11-24 00:34:16 · answer #4 · answered by jon_yao 2 · 0⤊ 0⤋
x = 32.
2006-11-24 00:34:41 · answer #5 · answered by bob the matrix 2 · 0⤊ 0⤋