Q: A numismatist decides to divide his coin collection between his children.
The oldest gets 1/2 of the collection, the next gets 1/4, the next gets 1/5,
and the youngest gets the remaining 49 coins.
How many coins are in the collection?
2006-11-24 00:26:53 · 11 answers · asked by Devil inc.. 1 in Education & Reference ➔ Homework Help
1/2 + 1/4 + 1/5 = 19/20 [ the first three kids]
remainder = 49 coins
20/20 - 19/20 = 1/20
therefore, 1/20 = 49 coins
if 1/20 = 49, then, 19/20 =
19 x 49 = 931 coins
altogether = 1/20 + 19/20
= 49 + 931
= 980 coins in the collection.
2006-11-24 01:11:13 · answer #1 · answered by Chemgurl 2 · 1⤊ 0⤋
I got the same answer too..
My working:
Let the total number of coins be X,
oldest 1/2X,
next 1/4X,
the other next! 1/5X,
youngest 49,
Therefore:
1/2X +1/4X +1/5X + 49 = X
X (1/2+1/4+1/5) + 49 = X
X (19/20) + 49 = X
49 = X - 19/20X
49 = 1/20X
X = 49 * 20
X = 980
2006-11-24 09:13:41 · answer #2 · answered by mr_nuclear_weapon 1 · 0⤊ 0⤋
980
2006-11-24 12:03:16 · answer #3 · answered by Olly Octopus 3 · 0⤊ 0⤋
980
2006-11-24 10:10:31 · answer #4 · answered by boo 1 · 0⤊ 0⤋
980
2006-11-24 08:40:15 · answer #5 · answered by Beau R 7 · 0⤊ 0⤋
980
2006-11-24 08:34:22 · answer #6 · answered by Lorenzo 3 · 0⤊ 0⤋
980
2006-11-24 08:31:43 · answer #7 · answered by Anonymous · 0⤊ 0⤋
x - x/2 -x/4 - x/5 = 49
20x - 10x - 5x - 4x = 49*20
x = 980
Therefore, no. of coins collected is 980.
2006-11-24 09:48:54 · answer #8 · answered by Naval Architect 5 · 0⤊ 0⤋
1/2+1/4+1/5=19/20
Therefore the youngest one got 1-19/20 or 1/20 th part of his collection
1/20 th part of collection=49
Total colletion=49X20=980
2006-11-24 08:30:44 · answer #9 · answered by alpha 7 · 0⤊ 0⤋
980 are the total coins
2006-11-24 08:36:12 · answer #10 · answered by Anonymous · 0⤊ 0⤋