x+8y = 60, 4x+4y = 60
subtract: first equation minus twice second equation
x + 8y = 60
-8x - 8y = -120
-7x = -60
x=60/7
Then plug x into one of the equations, say the first one
60/7 +8y = 60
8y = 60 - 60/7
8y = 360/7
y=45/7
2006-11-22 19:31:01
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answer #1
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answered by tj70555 2
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it extremely is solved in distinctive strategies like: divide the 2d equation by utilising 4 and it would be: x + y =15 then subtract it from the 1st equation: x + 8y =60 -x + y =15 the respond could be: 9y =40 5 divide the two factors by utilising 9 and you gets: y =5 use the two of the the two equations to locate x (i think of the 1st is plenty extra much less stressful when you consider which you do no longer multiply plenty) and replace it to y: x + 8(5) =60 x + 40 =60 then subtract 40 from the two factors: x + 40 - 40 =60 - 40 then you definately won x =20 you additionally can do any other way: double the 2d equation then it's going to be like this: 8x+8y =a hundred and twenty then do the stairs only like interior the 1st occasion: 8x - 8y =a hundred and twenty - x + 8y =60 then: 7x =60 divide the two factors and you will acquire x =60/7 replace and you gets y =40 5/7 attempt to confirm those solutions and you will locate that they are the two maximum astounding. sorry if that would not help plenty yet you are able to question me in case you had the different questions approximately math. i'm no longer that stable on the venture yet I nevertheless can assist you.
2016-11-26 02:44:34
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answer #2
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answered by ? 4
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x+8y=60 => x=60-8y
4x+4y=60 => x+y=15 => x=15-y
As the x values for both the equations are the same, we can write:
60-8y = 15-y
60-15 = 8y-y
45 = 7y
y = 45/7
y = 6 3/7
Substi y = 6 3/7 into x=15-y,
x = 15 - 6 3/7 = 8 4/7
So x = 8 4/7 and y = 6 3/7
2006-11-26 02:41:50
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answer #3
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answered by Kemmy 6
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I don't think that it's impossible. Use substituition or elimination.
eqn 1 - eqn 2 / 4 ->
7y = 45, solve for y, then use either equation to solve for x...
x = 15-y = 15 - 6 3/7 = 8 4/7
Check:
8 4/7 + 8(6 3/7) = 8 4/7 + 48 + 24/7 = 56 28/7 = 60 , OK it checks....
2006-11-22 19:33:58
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answer #4
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answered by modulo_function 7
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x + 8y =60 and 4x + 4y =60
=>x + 8y =60 and 8x + 8y =120
{x + 8y =60} - {8x + 8y =120}
=>{x - 8x} + {8y-8y} = {60 - 120}
=> -7x = -60
=> x = 60/7
Now, x + 8y =60 and x = 60/7
=> (60/7) + 8y = 60
=> 8y = 60 - (60/7)
=> y = {60 - (60/7)}/8 = 360/56 = 45/7
So, answer is (x,y) = (60/7, 45/7)
2006-11-22 20:35:31
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answer #5
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answered by Paritosh Vasava 3
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i) x + 8y =60
ii) 4x + 4y =60
i) => x = 60 - 8y
ii) 4x + 4y = 4(60 - 8y) + 4y = 60
240 - 32y + 4y = 60
180 = 28y
y = 180/28 = 45/7
i) x + 8y =60 = x + 8*45/7
x = 60 - 360/7 = (420 - 360)/7 = 60/7
x = 60/7
y = 45/7
/************/
check (ii)
4x + 4y = = 4( x + y) = 4 (60 + 45)/7 = 4*105/7
= 420/7 = 60
hmm good answer ..
good luck
2006-11-22 19:31:23
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answer #6
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answered by atheistforthebirthofjesus 6
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If 4x +4y = 60 then x+y=15/2, then all you have to do is find out how to do the rest. Try asking your teacher. It's too early in the morning for me to start doing your homework for you, but x=60/7 and you can do the rest for yourself
2006-11-22 19:54:36
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answer #7
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answered by Dover Soles 6
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x+8y=60........(1)
4x+4y=60......(2)
multiply (2) by 2
8x+8y=120
subtract (1) from(2)
7x=60
x=60/7
substitute x into (1)
60/7+8y=60
multiply by 7
60+56y=420
56y = 360
y=45/7
therefore, x=60/7 and y=45/7
i hope that this helps
2006-11-22 19:48:44
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answer #8
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answered by Anonymous
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x + 8y =60.....Eq 1
4x + 4y =60.....Eq 2
Consider Eq 2
4x + 4y =60
4(x + y) = 60
x + y = 60/4
x + y = 15.....Eq 3
x = 15-y
Substitute the value of x in Eq 1
x + 8y = 60
15-y + 8y = 60
15 + 7y = 60
7y = 60-15
7y = 45
y = 45/7
Substitute the value of y in Eq 3 to find 'x'
x + y = 15
x + 45/7 = 15
x = 15-45/7
x = 105/7 - 45/7
x = (105 - 45)/7
x = 60/7
The ordered pair solution is:
(60/7, 45/7)
2006-11-22 19:25:59
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answer #9
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answered by Akilesh - Internet Undertaker 7
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The answer is (x,y) = (60/7, 45/7)
2006-11-22 22:22:50
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answer #10
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answered by amit 1
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