I keep messing up. Help would be greatly appreciated :)
(x³ + 4x²y + 2 xy² + 3y³) - (5xy² -2y³ + 6x²y)
2006-11-22 18:56:01 · 7 answers · asked by Sally 1 in Science & Mathematics ➔ Mathematics
(x³ + 4x²y + 2xy² + 3y³) - (5xy² -2y³ + 6x²y)
x³ + 4x²y + 2xy² + 3y³ - 5xy² + 2y³ - 6x²y
x³ + 4x²y - 6x²y + 2xy² - 5xy² + 3y³ + 2y³
x³ + (4-6)x²y + (2-5)xy² + (3+2)y³
x³ - 2x²y - 3xy² + 5y³
2006-11-22 19:01:19 · answer #1 · answered by Jim Burnell 6 · 1⤊ 0⤋
(x³ + 4x²y + 2 xy² + 3y³) - (5xy² -2y³ + 6x²y)
= x³ + 4x²y + 2 xy² + 3y³ - 5xy² +2y³ - 6x²y
= x³ + (4-6)x²y + (2-5) xy² + (3+2)y³
= x³ - 2x²y - 3xy² + 5y³
2006-11-23 04:39:13 · answer #2 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
Subtraction is like adding the opposite. So just change the signs of the terms in the subtrahend and then add.
X^3 + 4X^2Y + 2XY^2 + 3Y^3 - 5XY^2 + 2Y^3 - 6X^2Y =
X^3 - 2X^2Y - 3XY^2 + 5Y^3
2006-11-23 03:13:46 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(x³ + 4x²y + 2 xy² + 3y³) - (5xy² -2y³ + 6x²y)
= x³ + 4x²y + 2 xy² + 3y³ - 5xy² +2y³ - 6x²y
= x³ + 4x²y - 6x²y + 2 xy² - 5xy² + 3y³ +2y³
=x³ - 2x²y - 3xy² + 5y³
2006-11-23 03:09:50 · answer #4 · answered by Anonymous · 1⤊ 0⤋
(x³ + 4x²y + 2 xy² + 3y³) - (5xy² -2y³ + 6x²y)
= x³ + 4x²y + 2xy² + 3y³ - 5xy² +2y³ - 6x²y
= x³ - 2x²y - 3xy² + 5y³
2006-11-23 03:13:31 · answer #5 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
(x² + 4x²y + 2xy² + 3y²) - (5xy² - 2y² + 6x²y)
x² + 4x²y + 2xy² + 3y² - 5xy² +2y² - 6x²y
x²+ 4x²y -6x²y + 2xy² - 5xy² + 3y² + 2y²
x² - 2x²y - 3xy² + 5y²
- - - - - - -s-
2006-11-23 07:19:02 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
i am sorry that i cant show you the method but the simplified result will be -3+3y
2006-11-23 12:28:48 · answer #7 · answered by sara 2 · 0⤊ 0⤋