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Please give me a good answer. It's for my exam.

2006-11-22 18:08:59 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

The addition rule is a result used to determine the probability that event A or event B occurs or both occur.


The result is often written as follows, using set notation:
P(A U B) = P(A) + P(B) - P(P int B)

where:
P(A) = probability that event A occurs
P(B) = probability that event B occurs
P(A U B) = probability that event A or event B occurs
P(A int B) = probability that event A and event B both occur

Proof:

For mutually exclusive events, that is events which cannot occur together: P(A int B) = 0
The addition rule therefore reduces to
P(A U B)= P(A) + P(B)

For independent events, that is events which have no influence on each other:
P(A int B) = P(A).P(B)
The addition rule therefore reduces to
P(AUB)=P(A)+P(B)-P(A).P(B)

In both cases the rules stands true.

This can also be proved with venn diagram.

I hope I answered your question.

All the best

2006-11-22 21:08:00 · answer #1 · answered by Paritosh Vasava 3 · 1 2

Addition Theorem

2016-10-14 11:40:38 · answer #2 · answered by ? 4 · 0 0

Addition Law Of Probability

2017-01-05 09:30:43 · answer #3 · answered by veasman 4 · 0 0

You could ask "how do you write a tune". There are many ways. Most identity proofs follow a LHS RHS pattern You begin with the Left Hand side of the identity, and attempt to manipulate it or simplify it until it forms the right hand side.

2016-05-22 21:03:08 · answer #4 · answered by Anonymous · 0 0

that is one of the most important in probability statistics.
the equation for this goes this way

Pr(A or B) = Pr(A) + Pr(B) - Pr(A and B)


The union of the sets is equal to the sum of probability A and B minus the probability A and B or their intersection.

2006-11-22 18:27:49 · answer #5 · answered by jdash01 3 · 0 0

Your exam will almost certainly want what's been provided in the course. Did you lose the textbook?

2006-11-22 18:11:18 · answer #6 · answered by modulo_function 7 · 0 0

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