where does 9.8 m/s to gravity (squared) come from? from what equation? from who?

Answer 1

Newton. Freely falling bodies fall at a constant rate. Distance/Time.

Answer 2

First of all note that the all bodies are pulled toward earth with a constant acceleration (irrespective of the mass of the object).

This acceleration due to gravity can be measured experimentally.

There are numerous methods to calculate experimentally the value of g.

By doing so many experiments it is found that at each place on the earth’s surface the value of g is a constant.

In general the value is taken to be 9.8m/s^2.

A simple experiment to find the value of g is to use a simple pendulum.

By observing the period of oscillation of a simple pendulum and measuring the length of the simple pendulum one can determine the acceleration due to gravity very accurately.

The period T is related by the equation T = 2xpi x square root of (length/ acceleration due to gravity.

Answer 3

Gravitational Force on Earth = G × mass of earth × mass of object / radius of earth squared

F = G×M_earth×M_you / r^2
or
g = G×M_earth/ r^2

Where G is the gravitational constant of 6.6742×10^-11 N*m^2/kg^2
Mass of earth = 5.9742×10^24 kg
Mean radius of earth = 6,372,797 m

g = (6.6742×10^-11 N*m^2/kg^2)×(5.9742×10^24kg)/ (6,372,797m)^2

g= 9.8179 m/s² which is very close to the accepted answer of

g= 9.80665 m/s²

Answer 4

you can work it out like this. (it really works try it and it is very simple)

9.8m/s^2 is an acceleration. (the first thing to know)

take any object and raise it to a specific height.(note the height)
drop it and note the time it takes to hit the earth.(note the time)

calculate the average velocity = total height / total time taken
=height / time= h / t . (h/t is the average velocity)


Now we have to find the final velocity (the velocity with which the object hits the earth) take it (Vf= final velocity)

and take the initial velociy = Vi which is equal to zero ofcourse.

now we have another formula

(Vf-Vi)/2= average velocity

we have already found the average velocity

(Vf+Vi)/2= h/t
Vf+Vi = 2h/t
Vf = 2h/t - Vi (this is how we can calculate the final velocity(Vf))
Vf= 2h/t (Vi = 0 this is the starting velocity)

now the formula of acceleration as u know is
(Vf-Vi)/t

substitute the values and u will get the gravitaional acceleration easily. remember Vi is zero because it is the initial velociy.

You can also find it through the Universal Law of gravitation as some other users have explained above. but for that u have to know the derivation of the "Universal Law of gravitation" it is itself very complex.

Answer 5

The acceleration due to gravity can be measured experimentally. Buy a phototimer pulley, some counterweights, and measure the acceleration yourself. At around ground level, for a normal sized object on earth, it happens to be around 9.8m/s^2.

Answer 6

F=GMm/r^2

F=force of gravity
G=gravitational constant
M=mass of object one
m=mass of object two
r=distance between 2 objects in meters.

http://physics.webplasma.com/physics08.html

Answer 7

I suppose you've not heard of Newton? His Universal Law of Gravitation? That gravitational attraction is proportional to the mass of an object?
http://en.wikipedia.org/wiki/Gravity

Answer 8

x^2 - 2x + y^2 + 2y - 98 = 0 ==> (x -1)^2 -1 + (y+1)^2 - 1 - 98 = 0 ==> (x-1)^2 + (y+1)^2 = 100 so, centre at (1, -1) and radius 10

Answer 9

It just is. It's the one law that can't be broken.

Answer 10

you may search www.google.com for it . there you may find a site which has the correct matter for you .