A 2.1*10^-4 kg spider is suspended from a thin strand of spider web. the greatest tension the strand can withstand without breaking is 2.0*10^-3 N. What is the maximum acceleration with which the spider can safely climb up the strand?
ps- the "^" means power of :)
thx for your help guyz
2006-11-22 16:54:24 · 3 answers · asked by navratna s 1 in Science & Mathematics ➔ Physics
After doing this problem on a free body diagram and using Newton's second law I found .286 m/s^2 as the answer. This assumes using g=9.81 m/s^2
My equation on the free body diagram:
T-mg=ma
And in its final form:
a=g-T/m
2006-11-22 17:13:06 · answer #1 · answered by Zach 1 · 0⤊ 0⤋
The tension in the strand will be the weight of the spider = m*g plus the accelerating force = a*m; the total tension is then
T = m*(g+a). Plug in T, m, g and solve for a.
2006-11-23 00:59:45 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
yes; it works against accerlation like lift is going upwards(g+a).
mass=2.1*10^4, F=2.0*10^-3
F=M*A;
A=F/M=0.99*10^-7
2006-11-23 01:04:09 · answer #3 · answered by anupam s 1 · 0⤊ 0⤋