How it all works
One of the questions that everyone inevitably asks is "why is it called burning?" To answer that question, let's step back and take a look at how a CD actually works. Remember that all computer data, regardless of what type, is stored as zeros and ones. The computer then interprets the zeros and ones to make sense out of the madness. We used to have punch cards that did the trick. Now we have hard drives that store data in magnetic form. CDs are no different. On a CD, the "roughness" of the CD's surface represents the zeros and ones. This may come as a shock to you, since a CD's surface appears seemingly smooth to you. But make no mistake about it, there are incredibly small pits and grooves etched on the surface of the CD. Each pit represents a bit of data. (So the more pits you can pack into a CD, the more data it can store. Currently, normal CDs store about 650MB of data, or 74 minutes of audio.) When a CD is inserted into the CD-ROM drive, a small laser inside the CD-ROM drive is shot onto the surface of the CD. After the laser hits the surface, it will be reflected off the CD's surface. The reflected light is then intercepted by a series of mirrors and sensory devices, which analyzes the light and determines the bit the light represents. The digital signal processor in the CD basically analyzes the brightness of the reflected light. If the brightness is above a certain threshold, it is interpreted as a one. Otherwise, it is a zero. The brightness of the reflected light is directly related to the pits and grooves on the CD. If the light reflected off a huge pit in the CD, then the reflection would not be very bright. (because of scattering. Just as your image, viewed in a worn down mirror, will not be very clear.) Thus, a large pit is interpreted as a zero. Conversely, a smooth area on the CD, called lands, would reflect very well, and thus is interpreted as a one.
So now that we have a basic understanding of how CDs actually work, it's time to take a look at how CD writers perform their magic. If you've ever seen the backside of a brand new, unwritten, CDR disc (So yes, there are blank CDs. You can buy them at most of your major computer retailers, like Comp USA, or Best Buy.), you would notice that it is surprisingly reflective. A blank CD, in fact, has no pits (for the experts reading this article, I am of course making a oversimplification by ignoring the pre-grooved spiral track layer used to guide the burning laser). So if your computer were to scan the CD, it would read all zeros. When you actually write data on to the CD (and we'll be getting to that a little bit later in the article), the laser inside the CDR drive (from this point on, I will be referring to all types of CD writing drives as CDR) actually heats the surface of the blank CD up so that the chemical coating of the CD will react and form a pit. That is why most people refer to CD Copying as CD burning. In essence, you are burning a pit into the CD. Once the CD is written, you will notice that the backside is no longer as reflective as it used to be. The pits are now on the CD, and they don't reflect as much light as the smooth surface. There you have it - the magic behind CD writing.
2006-11-23 00:49:06
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answer #2
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answered by LadieVamp 5
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Because like something once burn't cannot be restored back; a CD once written cannot be restored back to its original state. However, this is true for the write-once-read-many-times CD's only. The erasebale type of CD's can be written, erased and re-written.
2006-11-23 00:56:29
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answer #4
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answered by Rajendra Singh 1
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because lazer will burn the disk in the form of pits and land
so its called like that some time cd will burn inside the rom if ur cd rom lenceis over heated
2006-11-23 03:02:59
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answer #5
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answered by Arun K M 2
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THE WRITING PROCESS IS A TECHNICAL YAG LASER PROCESS IN WHICH THE DATA IS TRANSMITTED INTO BOOLEAN FORM AND STORED INTO CDs . THE DATA ONCE TRANSMITTED INTO CDs CAN THEN NEVER BE CHANGED OR DISTORTED . THE INFORMATION ARE BURNED IN THE FORM OF DATA IN THE CDs. "ROBIN"
2006-11-23 03:34:40
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answer #7
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answered by rbn_verma 2
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