to play super lotto 6/49, a person chooses 6 numbers out of a possible 49. the lottery corporation then randomly chooses 6 numbers as well. how many possible six-number sets can be chosen by the lottery corporation that match exactly 4 out of the numbers that you choose? show your solution.
2006-11-22 14:50:28 · 2 answers · asked by rod_dollente 5 in Science & Mathematics ➔ Mathematics
There are 6 correct numbers.
That means 49-6 = 43 numbers are incorrect.
You need to choose 4 correct numbers and 2 incorrect numbers.
C(6,4) = 15
C(43,2) = 903
15*903 = 13545
2006-11-22 14:56:09 · answer #1 · answered by MsMath 7 · 2⤊ 1⤋
Possible no of combinatons
No of 4 number combinations you have = 6C4 = 15
Number of possible combimations from lotto = those four you have plus 2 others you do not have and there are 43C2 of those
ie 43 * 21 = 903 (which is not many really)
2006-11-22 22:54:55 · answer #2 · answered by Wal C 6 · 1⤊ 1⤋