The formula is 10C7 (2x)^3 (2y)^7
This comes out 122880x^3y^7
2006-11-22 12:38:04
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answer #1
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answered by hayharbr 7
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There's a standard formula for this. The r'th term is
nC(r-1)*((2x)^(n-(r-1)))*(2y)^(r-1)
[After posting, I had a look at this and noticed that the last exponent appears only as dots ... No idea why. Anyway, I hope you know already that it's r-1)
In this case you have n = 10 and r = 8. I think you can take it from there. Remember 10C7 is equal to 10C3, so that makes it even easier.
2006-11-22 20:39:48
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answer #2
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answered by Hy 7
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(2x + 2y)^10 = 1024x^10 + 10240x^9y + 46080x^8y^2 + 122880x^7y^3 + 215040x^6y^4 + 258048x^5y^5 + 215040x^4y^6 + 122880x^3y^7 + 46080x^2y^8 + 10240xy^9 + 1024y^10
The 8th Term is 122880x^3y^7
If you go to www.quickmath.com, click Expand under Algebra, type in (2x + 2y)^10, then click expand and it will give you what i have given you.
2006-11-22 20:46:37
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answer #3
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answered by Sherman81 6
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4xy to the 10th is 4(10th)xy
2006-11-22 20:35:05
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answer #4
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answered by skull-rider 1
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it depends on what numbers x and y stand for
2006-11-22 20:39:39
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answer #5
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answered by shadow_the_echinda 2
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ur mom learn math
2006-11-22 20:35:44
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answer #6
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answered by Anonymous
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go to calculator on windows
2006-11-22 20:34:41
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answer #7
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answered by Columbus614Ohio 2
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do ur own homework
2006-11-22 20:36:04
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answer #8
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answered by thugglifeson81 1
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