How do you simplify (2x+1)/(x^2)?

Question

please also give an answer

It is 2x+1 divided by (x^2). notice the "/"
Please help

Answer 1

It seems to me that is the simplest form already.

Answer 2

If this is written correctly, then it seems to be in simplest form. You could go ahead and perform the division, which gets you this result:

(2x/x^2) + (1/x^2) = (2/x) + (1/x^2).

We could re-write the above as (2x^-1) + (x^-2). Notice that the numbers in parentheses are variables raised to powers, not polynomials.

Now we can factor out an x^-1 factor. If we do this, we get:

x^-1(2+x^-1).

We read this as x to the negative first power times the quantity 2 plus x to the negative second power. However, I am not so sure this is in any simpler form than the original expression.

Answer 3

To simplify first remove parentheses
and use distributive property of multiplication
x^2 will be multiplied to 2x and to 1
:remember multiplying numbers with the same base (specifically with x) add exponents of base (x) and multiply the coffeffients of course ,so (2x) (x^2) + (x^2)(1) is 2x^3 +x^2 now that all parentheses are removed the answer 2x^3 +x^2 is final solution

Answer 4

Distribute.

x^2(2x) + x^2(1)=

2x^3+x^2

Answer 5

Yes it is really in the most simple form
however you can write it in alternative forms like this:
(2x+1)/x^2=(2x/x^2)+(1/x^2) hence
2/x+1/x^2 if u wish

Answer 6

Multiply the X^2 through the bracket. So the answer would be 2X^3 + X^2

Answer 7

2/x+1/(x^2)

Answer 8

(2x+1)/(x^2)
distribute the x^2 into the 2x + 1
2x^3 + x^2

Answer 9

When you divide, its the same as x^-2

Therefor, you can rewrite the equation as (2x + 1) (x^-2)

obviously you expand for simplicity reasons.

2x^-3 + x^-2

Answer 10

7

Answer 11

(2x + 1)/(x^2)

The only other way to do this is

((2x)/(x^2)) + (1/(x^2))
(2/x) + x^(-2)
2x^-1 + x^(-2)

Other than that, there is no real way to simplify this any further.