i need help please with this problem?

Question

Find the length of the unknown side of the triangle. Give the exact length and a one-decimal-place approximation.
length of one side is 5m. and the longer side of the triangle is 9 and the sqaure root of 3m ( the 3m is under the radical sign and the 9 is on the outside of the radical sign.). this is the only one that I have and I need some help please on how to get the answer. I know the formula is a^2+b^2=c^2
but it keep coming up wrong and I need to get the length in length and the decimal length. I'm not doing something right.help please

Answer 1

I suppose the triangle is right-angled.
Let the unknown side be 'x'
In that case,
5^2 + x^2 = [9*(sqrt3)]^2
25 + x^2 = 243
x^2 = 243 - 25
x^2 = 218
x = sqrt(218)
= 14.7648230602334(approx)

Answer 2

If it is a right triangle, use pythagorean theorem

5^2 + X^2 = (9 radical 3)^2
25 + X^2 = 243
X^2 = 218
X = 14.8 (approximately to the tenth)
Remember when squaring a number radical number
X sqr root Y
its then X^2 * Y
since sqr root of Y * sqr root of Y = Y
so 81 * 3= 243

Answer 3

Is this a right triangle? If it is you can use the pythagorean theorem which is a^2 + b^2 = c^2. What's the hypotenuse?
let's assume that you're trying to find the hypotenuse in which case
(5)^2 + (9sqrt(3))^2 = c^2
25 + 243 = c^2
268 = c^2
c = 2(sqrt(67))
c is rounded to 16.4

if 9 and the sqrt of 3 is the hypotenuse, then
(5^2) + b^2 = (9sqrt(3))^2
25 + b^2 = 243
b^2 = 218
b = sqrt(218)
b is rounded to 14.8

Answer 4

16.3

sqrt((9(sqrt(3)))^2 + 5^2)=16.3