i need help with this math problem?

Question

tan30 x sen45 + cot120

Answer 1

1/rt3 *1/rt2-1/rt3
[1/rt3](1/rt2-1)
[1/rt3](1-rt2/rt2)
rationalising
[(1-rt2)*rt6]/6

Answer 2

Remember everything relates to the unit circle. (cos x, sin y)

tan(30) = y/x or sin(30)/cos(30) so...
tan(30) = (1/2)/(√3/2)
tan(30) = 2√3/6

sin(45) = x
sin(45) = √2/2

cot(120) = x/y or cos(120)/sin(120)
cot(120) = (-1/2)/(√3/2)
cot(120) = -√3/3

so back to the original equation:
tan30 x sen45 + cot120

(2√3/6)(√2/2) + -√3/3 = X
(0.577)(0.707) - 0.577 = X
X = -0.169061

I believe Steve actually gave you the right answer. I was just trying to expand on how he got it.

Answer 3

tan30 x sen45 + cot120 = (1/sqrt3 )(1/sqrt2) -1/sqrt3
=1/sqrt(3) [ 1/sqrt(2) -1 ] '

Answer 4

tan30 x sen45 + cot120
tan 30 = (sqrt(3))/3
sin 45 = (sqrt(2))/2
cot 120 = -sqrt(3)
[(sqrt(3))/3][(sqrt(2))/2] - sqrt(3)
(sqrt(6))/6 -sqrt (3)
[sqrt(6) - 6sqrt(3)]/6

Answer 5

First - sen is unknown; Under the assumption you mean secant
the answer is tan(30) * 1/cos(45) + 1/tan(120) = ~.2391

If you want you can simplify this noting that tan = sin/cos,
and similar.

Answer 6

I'm not sure what the problem is. If you wish to evaluate this expression, and 'sen' is really sin, then

tan30*sin45 + cot 120 = .57735*.7071 + (-.57735) = -.1691

Answer 7

I don't know what the letters are for but the answer i got is 3'600.00,i hope it is right!