i just don't seem to get these, please tell me the answer and how you got it:
Find x: ax - bx = 6
2006-11-22 06:30:27 · 12 answers · asked by mr yass 2 in Science & Mathematics ➔ Mathematics
take out the x
x(a-b)=6
x=6/(a-b)
2006-11-22 06:32:50 · answer #1 · answered by 7 · 3⤊ 0⤋
ax - bx = 6
Use the distributive property to isolate x:
(a - b)x = 6
Now divid bothe sides by (a - b):
x = 6 / (a - b)
2006-11-22 06:33:41 · answer #2 · answered by Anonymous · 2⤊ 1⤋
Factor x out
ax-bx=6
x(a-b)=6
x=6/(a-b)
Note a cannot equal b as division by 0 occurs which is not allowed
2006-11-22 06:33:09 · answer #3 · answered by Oz 4 · 2⤊ 1⤋
ax - bx = 6
x(a-b)=6
>>>x=6/(a-b)
subject to the restriction
{a is not equal to b}
i hope that this helps
2006-11-22 07:49:13 · answer #4 · answered by Anonymous · 1⤊ 1⤋
(x)=x^3+ax^2+bx-6 if remainder when f(x) is divided by (x-2) = remainder when f(x) is divided by (x+2) show that b=-4
By the remainder theorem, f(2)=f(-2). Let's plug in the numbers and see
what happens:
8 + 4a + 2b - 6 = -8 + 4a -2b - 6
16 + 4b = 0
4b = -16
b = -4
good luck, hope this is right
2006-11-22 06:37:04 · answer #5 · answered by missey01_uk 3 · 1⤊ 2⤋
ax - bx = 6
Factor out x to get:
x(a-b) = 6
Now divide both sides by a-b to get
x = 6/(a-b)
2006-11-22 06:34:57 · answer #6 · answered by ironduke8159 7 · 2⤊ 1⤋
ax - bx = 6
Factor out an x
x(a-b) = 6
Divide both sides by (a-b)
x = 6/(a-b)
Note that a-b cannot be zero (because you can't divide by zero).
2006-11-22 06:32:57 · answer #7 · answered by MsMath 7 · 1⤊ 2⤋
Take out a factor of x
x(a-b) = 6
Then divide both sides by (a-b)
x=6/(a-b)
note that this is not true when a=b because you can't divide by 0!
2006-11-22 06:42:15 · answer #8 · answered by drummanmatthew 2 · 1⤊ 1⤋
x=6/(a-b)
2006-11-22 09:05:04 · answer #9 · answered by Just me 5 · 1⤊ 1⤋
ax-bx=6
x(a-b)=6
x=6/(a-b)
2006-11-22 16:55:00 · answer #10 · answered by sam 3 · 0⤊ 0⤋
ax - bx = 6
x(a - b) =6
So x = 6/(a - b)
2006-11-22 06:38:28 · answer #11 · answered by Wal C 6 · 2⤊ 1⤋