Factorise?

Question

Can anyone factorise:

-3X^2+16X+6

Answer 1

Well, the first thing i would do is change the signs round so there isn't a negative x(^2)....so u get 3x(^2)-16x-6=0
This cannot be perfectly factorised into 2 brackets so then use the formula -b(+or-) (root of b(^2)-4xaxc)/2a
This gives u -(-16)(+or-) (root of -16(^2)- 4x3x-6)/2x3
Simplified it makes 16(+or-) (root328)/6 and gives u 2 solutions
Rounded to 2 decimal places, these are 5.68 & -0.35
Hope u understand this, & hope its right too!

Answer 2

multiply the equation through by -1
3x^2-16x-6 = 0 say

use the quadratic formula

x=8/3+or - sqrt(328)/6
=2.66666667 + or - 3.018461713
=5.68512838 or -0.351795046
therefore,
(x+0.351795046)
(x-5.68512838)=0

we want to get this equation into
the form -3X^2+16X+6=0

try multiplying first factor by -3
(it will still be equal to 0)

(-3x-1.055385138)
(x-5.68512838)=0

therefore, -3X^2+16X+6
=(-3x-1.055385138)
(x-5.68512838)

if you work out the above factors with
your calculator you will find that
they are very near for an
irrational solution

i hope that this helps

Answer 3

Not into any rational factors (ax + b)(cx + d), because the "discriminant" of this quadratic is 16^2 + 4*3*6 = 328 which is not a perfect square.

Answer 4

-(3x^2-16x-6)
the roots of 3x^2-16-6 are
x=[16+/-rt(256+72)]6
=[16+/-rt328]/6
=[16+2rt82]/6
=[8+/-rt82]/3
so the factors would be
-[x-8-rt82][x-8-rt82]/9

Answer 5

im not sure what exactly you want but 25x + 6 would be the answer if you just wanted it worked out