simplify (x^2+6x+8) / (x^2-4x-21) / (x^2-4) / (x^2-7x)
show working please
2006-11-22 01:30:21 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I presume you mean
[(x^2+6x+8) / (x^2-4x-21)] / [(x^2-4) / (x^2-7x)]
2006-11-22 01:40:01 · answer #1 · answered by ? 6 · 0⤊ 0⤋
(x^2+6x+8) / (x^2-4x-21) / (x^2-4) / (x^2-7x)
Factor the polynomials and use the reciprocal thing to divide because its form is like a fraction:
(x+4)(x+2)x(x-7) / (x-7)(x+3)(x-2)(x+2)
Cancel out the factors that are contained in the numerator and the denominator:
x(x+4)/(x+3)(x-2)
(x^2+4x) / (x^2+x-6)
2006-11-22 09:52:41 · answer #2 · answered by Lin 2 · 0⤊ 0⤋
(1/(x+3))(x/(x-2))
2006-11-22 09:33:19 · answer #3 · answered by 7 · 0⤊ 0⤋
x2+6x+8 x2-7x
------------ X -------------------
x2-4x-21 x2-4
= x^4-42x+8
----------------
x^4 -4x +84
=21x+2
------------- Answer
2x+21
2006-11-22 10:23:26 · answer #4 · answered by Ashwin M 3 · 0⤊ 0⤋