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Cameron's frequent-flyer program requires 50,000 miles (mi) for a free domestic flight. During the past year, he accumulated 25,250 miles. During this year, he took three more flights of 2,600, 1,425, and 4,260 mi. How much farther must he fly for his free trip?

can someone SHOW me how this is worked out..

thanks

2006-11-22 01:22:54 · 6 answers · asked by CrazyBlueEyedGirl13 1 in Science & Mathematics Mathematics

6 answers

Add up all the miles he has, and subtract from 50,000
50,000 - (25,250 + 2,600 + 1,425 + 4,260) = ______

2006-11-22 01:25:01 · answer #1 · answered by pohustla 2 · 1 0

25,250 + 2,600 + 1,425 + 4,260+x = 50,000
33,535 + x = 50,000

now subtract 33,535 from both sides

33,535 - 33,535 + x = 50,000 - 33,535
0 + x = 16,465
x = 16,465 miles to go

2006-11-22 01:29:18 · answer #2 · answered by Andy M 3 · 1 0

needs 50,000
has 25,250
obtained 2,600 + 1,425 + 4,260

add this to the 25,250 and he has 33,535

since he has 33,535 the difference is 50,000 - 33,535 = 16465

he needs 16,465 more miles

2006-11-22 01:26:43 · answer #3 · answered by Anonymous · 0 0

16465, assuming he gets one-for-one miles.

Just add up the number of miles from this year's trips, then add that number to 25,250, and then subtract the result from 50,000

2006-11-22 01:25:53 · answer #4 · answered by Stretchy McSlapNuts 3 · 0 1

Number of miles covered last year = 25250 miles
Number of miles this year = 2600+1425+4260
= 8285 miles
Total miles covered = 25250 + 8285
= 33535 miles
Miles required for trip = 50000 miles
No. of miles required = 50000 - 33535
= 16465 miles

2006-11-22 03:34:28 · answer #5 · answered by Akilesh - Internet Undertaker 7 · 0 0

2,600+1,425+4,260+25,250+X=50,000
33,535+X=50,000
(33,535-33,535)+X=50,000-33,535
X=16,465

Hope this is helpful

2006-11-22 01:36:32 · answer #6 · answered by Ken K 1 · 1 0

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