Cameron's frequent-flyer program requires 50,000 miles (mi) for a free domestic flight. During the past year, he accumulated 25,250 miles. During this year, he took three more flights of 2,600, 1,425, and 4,260 mi. How much farther must he fly for his free trip?
can someone SHOW me how this is worked out..
thanks
2006-11-22
01:22:54
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6 answers
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asked by
CrazyBlueEyedGirl13
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Science & Mathematics
➔ Mathematics
Add up all the miles he has, and subtract from 50,000
50,000 - (25,250 + 2,600 + 1,425 + 4,260) = ______
2006-11-22 01:25:01
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answer #1
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answered by pohustla 2
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25,250 + 2,600 + 1,425 + 4,260+x = 50,000
33,535 + x = 50,000
now subtract 33,535 from both sides
33,535 - 33,535 + x = 50,000 - 33,535
0 + x = 16,465
x = 16,465 miles to go
2006-11-22 01:29:18
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answer #2
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answered by Andy M 3
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needs 50,000
has 25,250
obtained 2,600 + 1,425 + 4,260
add this to the 25,250 and he has 33,535
since he has 33,535 the difference is 50,000 - 33,535 = 16465
he needs 16,465 more miles
2006-11-22 01:26:43
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answer #3
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answered by Anonymous
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16465, assuming he gets one-for-one miles.
Just add up the number of miles from this year's trips, then add that number to 25,250, and then subtract the result from 50,000
2006-11-22 01:25:53
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answer #4
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answered by Stretchy McSlapNuts 3
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Number of miles covered last year = 25250 miles
Number of miles this year = 2600+1425+4260
= 8285 miles
Total miles covered = 25250 + 8285
= 33535 miles
Miles required for trip = 50000 miles
No. of miles required = 50000 - 33535
= 16465 miles
2006-11-22 03:34:28
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answer #5
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answered by Akilesh - Internet Undertaker 7
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2,600+1,425+4,260+25,250+X=50,000
33,535+X=50,000
(33,535-33,535)+X=50,000-33,535
X=16,465
Hope this is helpful
2006-11-22 01:36:32
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answer #6
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answered by Ken K 1
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