i have no idea how to do this! anyone know how to solve it?
csc^2x
---------=cot^2x
1+tanx
2006-11-21 18:55:01 · 3 answers · asked by quinn 2 in Science & Mathematics ➔ Mathematics
it doesnt make sense with csc? maybe its cos im not quite sure but can you try it with cos if you can>?
2006-11-21 19:10:24 · update #1
I think your identity should be :
csc^2(x) / [1 + tan^2(x)] = cot^2(x)
as you forgot to square the tan(x).
Working on the 1 + tan^2(x) gives:
1 + sin^2(x) / cos^2(x)
= [sin^2(x) + cos^2(x)] / cos^2(x)
= 1 / cos^2(x)
Now we have : csc^2(x) / [1 / cos^2(x)]
= [1 / sin^2(x)] / [1 / cos^2(x)]
= cos^2(x) / sin^2(x)
= cot^2(x), which was to be shown.
2006-11-21 19:13:25 · answer #1 · answered by falzoon 7 · 2⤊ 0⤋
do u mean cos wen u rite csc?
2006-11-21 19:04:54 · answer #2 · answered by Zeta 6 · 0⤊ 0⤋
There is some problem with your question. I tried almost all the ways, but cant reach RHS from LHS.
Sorry.
2006-11-21 22:56:12 · answer #3 · answered by Paritosh Vasava 3 · 0⤊ 0⤋