2006-11-21 16:26:22 · 5 answers · asked by ysu guy 1 in Science & Mathematics ➔ Chemistry
Commercial grade (98 to 99 percent) Tetraphenylcyclopentadienone (or 2,3,4,5-tetraphenylcyclopenta -2,4-dien-1-one) has a melting point of 217 to 220 drgrees C. The pure recrystalized specimen will usually melt at about 222 degrees using a vacuum melting point tube.
2006-11-21 18:06:20 · answer #1 · answered by Richard 7 · 47⤊ 1⤋
218 deg.C
Oh, as for the comment about remembering how to spell it...from the structure: "one" means a ketone. "cyclopentadien" means it's got a five-carbon ring, with two double bonds. The keto group goes the only place it can, at the one atom where there's no double bond. And the four phenyls attach to the other four carbons. Just one thing...shouldn't the IUPAC name be "tetraphenylcyclopentadieneone" (with an "e" after "dien")?
2006-11-21 16:40:20 · answer #2 · answered by pack_rat2 3 · 1⤊ 0⤋
Forget about its melting point!- How the heck do you remember how to spell it correctly?!
2006-11-21 16:34:35 · answer #3 · answered by Joseph, II 7 · 0⤊ 0⤋
lol i thought u said tetrahydrocannabinol
2006-11-23 02:36:56 · answer #4 · answered by jousfoub 2 · 1⤊ 0⤋
can u say it once again.!@$#%
2006-11-23 10:21:22 · answer #5 · answered by vicky 1 · 0⤊ 0⤋