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I was absent yesterday at school and missed out on how to do problems like this one.

2006-11-21 16:01:41 · 13 answers · asked by Anonymous in Science & Mathematics Mathematics

13 answers

FOIL Method

(5k + 2)(2k - 3) = 10k² - 15k + 4k - 6 = 10k² - 11k - 6

F = 2k x 5k = 10k²

O = 5k x -3 = - 15k

I = 2 x 2k = 4k

L = -3 x 2 = - 6


The answer is 10k² - 11k - 6


- - - - - s-

2006-11-21 23:43:34 · answer #1 · answered by SAMUEL D 7 · 0 0

All the solutions offered give a 'how', but no 'why'. Think about this:-

If 5k + 2 = y,
the question becomes
y(2k-3) which is a simple expansion yielding 2ky -3y.
Substitute for ' y ' ,
2ky - 3y = 2k(5k + 2) -3(5k + 2),
and expanding gives:-
10k^2 + 4k -15k -6 = 10k^2 - 11k -6

That is the ' why ' now the practical how is (and the order doesn't matter) :-

(5k+2)(2k-3) = 5k(2k - 3) + 2(2k - 3)
= 10k^2 - 15k + 4k - 6
= 10k^2 -11k - 6.

That first line is the important one, remember your rules for mult of positives and negatives. Write each step as I have and you will get it right every time. DO NOT TRUST YOURSELF TO DO BITS IN YR HEAD. The ' = ' should all be directly under each other, this system looses the formatting!

2006-11-22 02:22:39 · answer #2 · answered by Robert H 2 · 0 0

Use the technique called foil. First Inside Outside Last.

multiply the first two terms 5k(2k) = 10k^2
multiply the two inside terms 5k(-3) -15k
multiply the the two outside terms 2(2k) = 4k
multiply the two last terms 2 * -3 = -6

you now have 10k^2-15k+4k-6, combine all like terms and now you have 10k^2-11k-6

2006-11-22 00:10:17 · answer #3 · answered by ayok 2 · 1 0

Remember FOIL

First: 5k * 2k = 10k^2
Outside: 5k * -3 = -15k
Inside: 2 * 2k = 4k
Last: 2 * -3 = -6
Add all those answers up: 10k^2 -15k+4k-6
Simplified: 10k^2-11k-6

2006-11-22 00:09:06 · answer #4 · answered by MikeC 3 · 2 0

of course i can! I love this type of problem, it's called F-O-I-L which stands for (First, Outer, Inner, Last) this stands for the order you multiply the terms in:
Your problem reads (5k+2)(2k-3) here's your steps:
Step 1: Multiply the FIRST TERMS in each set of parenthesis: 5k*2k= 10k^2 (I don't know how to say it's squared, but it reads 10k-squared)
Step 2: Multiply the OUTER TERMS in each set of parenthesis:
5k*-3= -15K
Step 3: Multiply the INNER TERMS in each set of parenthesis:
2*2k= 4k
Step 4: Multiply the LAST TERMS in each set of parenthesis:
2*-3= -6
Then, after you get all of your answers, write them in a line

10k^2-15k+4k-6 and combine like terms
10k^2-11k-6 and that is your answer!!!

GOOD LUCK!!

2006-11-22 01:01:31 · answer #5 · answered by Buckwild 2 · 0 0

Step1: Multiply the two first terms in each of the parenthesis together. In this case 5k and 2k.
Step2: Multiply the two outer terms, the terms outside within the parenthesis. In this case 5k and -3.
Step3: Multiple the two inner terms, the terms deep inside the parenthesis. In this case 2 and 2k.
Step4: Multiply the two last terms, the terms that are last in each of the parenthesis. In this case the 2 and the -3.
Once you have all the products, you combine the like terms.

2006-11-22 00:12:56 · answer #6 · answered by ? 4 · 1 0

well if you're trying to expand the brackets..

i use the FOIL method which stands for FIRST, OUTER, INNER, LAST

in the sum (5k+2)(2k-3) you would times 5k and 2k first, then 5k and -3, then 2 and 2k, and finally 2 and -3

you would then get 10k2-15k+4k-6
then simplify it to 10k2-11k-6

2006-11-22 00:09:42 · answer #7 · answered by Anonymous · 1 0

take 5k times (2k-3) and 2 times (2k-3)
10k^2-15k+4k-6
ans: 10k^2-11k-6

2006-11-22 00:04:40 · answer #8 · answered by      7 · 2 0

(5k+2)(2k-3) use FOIL firt, outside, inside last.
1st: 10k^2
out: -15k
in: 4k
last: -6 add them all up
10k^2-11k-6

2006-11-22 00:21:30 · answer #9 · answered by yupchagee 7 · 1 0

(5k+2)(2k-3)
5k(2k-3) +2(2k-3)
(10k^2-15k)+(4k-6)
10k^2-11k-6

2006-11-22 06:57:32 · answer #10 · answered by Hana 2 · 0 0

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