I can seem to crack this problem.
2006-11-21 15:10:43 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use the FOIL method; First, Outer, Inner, Last.
First, n * n
Outer, n * 5
Inner, n * 7
Last 7 * 5.
Then add them all together.
22 NOV 06, 0420 hrs, GMT.
2006-11-21 15:16:24 · answer #1 · answered by cdf-rom 7 · 0⤊ 0⤋
That's the reduction of a binomial into its factors (roots).
Do you need to learn to multiply them?
Multiply the first number times the first, and the last times the last:
n*n = n^2, and 5*7 = 35
then the outsides (n * 7) and (n * 5). Add these. 5n + 7n = 12n
Now write down your polynomial
n^2 + 12n + 35
Done.
2006-11-21 23:16:57 · answer #2 · answered by ? 4 · 0⤊ 0⤋
~ (a + b)(c + d) = ac + ad + bc + bd ~
(n + 7)(n + 5)
= (n * n) + (n * 5) + (7 * n) + (7 * 5)
= n² + 5n + 7n + 35
= n² + 12n + 35
2006-11-21 23:48:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
N2 (squared) +12n+35
2006-11-21 23:12:31 · answer #4 · answered by Tim 2 · 1⤊ 0⤋
n^2+5n+7n+35=n^2+12n+35
2006-11-22 02:17:36 · answer #5 · answered by sam 3 · 0⤊ 0⤋
you can multiply them
n*(n+5)+7*(n+5)=
n^2"square"+5n + 7n+35
n^2 + 12n +35
2006-11-21 23:26:32 · answer #6 · answered by Loai K 1 · 0⤊ 0⤋
(n+7)(n+5) just use FOIL
n^2+5n+7n+35
n^2+12n+35
2006-11-21 23:26:09 · answer #7 · answered by yupchagee 7 · 0⤊ 0⤋
n² + 12n + 35
2006-11-21 23:14:29 · answer #8 · answered by M. Abuhelwa 5 · 1⤊ 0⤋
Make a smiley face by connecting two swooshes in the top for the eyes and two in the bottom for a nose and a mouth.
Then multiply and simplify.
2006-11-21 23:25:27 · answer #9 · answered by anonymous 4 · 0⤊ 0⤋
n^2+5n+7n+34
n^2+12n+34
2006-11-21 23:13:22 · answer #10 · answered by 7 · 0⤊ 1⤋