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part of the answer is a famous Mathmatician's name

2006-11-21 14:44:17 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Bionomial expansion

this has got n+1 terms

the terms are (nCk) a^kb^n-k where k varies from 0 to n

for example (a+b)^3
one term (3C0) a^0b^3 = b^3
another term (3C1)a^1b^2 = 3ab^2
another (3C2)a^2b^1 = 3a^2b
another (3c3)a^3b^0 = a^3

add them and get a^3+3a^2b+3ab^2+ b^3

(nCk) = n!/(k!(n-k)!)

The n'th line of the pascal triangle gives you the coeffiecients . Starting from 0.

2006-11-21 14:49:12 · answer #1 · answered by Mein Hoon Na 7 · 0 0

the answer is the binomial theorem, but I have a feeling that you want me to say using Pascal's triangle... the two are virtually equivalent anyway though.

2006-11-21 22:49:32 · answer #2 · answered by Texas Cowgirl 3 · 0 0

Pascal's triangle give you the coefficients.

2006-11-21 22:57:05 · answer #3 · answered by modulo_function 7 · 0 0

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