2006-11-21 14:34:45 · 3 answers · asked by dkplamann 1 in Science & Mathematics ➔ Chemistry
Start with one molecule Cl2/. Atomic weight: Cl=35.5, Cl2 = 71.
Multiply by 1molCl2/6.02x10^23molecules Cl2. The molecules Cl2 cancel, leaving mols Cl2. Multiply by 71gCl2/1molCl2. The molsCl2 cancel, leaving gCl2 in one molecule. The 6.02x10^23 is Avogadro's number. It may be good to express 71 as 7.1x10^2 in orderto use exponential notation throughout.
2006-11-21 14:48:03 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
first using theavogrado constant law one mole equals 6.02x10^23 thefore you solve for one molecule
then when you get that value probably a small one you multiply the mole by the molar mass of chlorine aka the atomic mass
2006-11-21 14:42:07 · answer #2 · answered by ayok 2 · 0⤊ 0⤋
Cl has an atomic weight of 35.5g/mol. so 1 mol of Cl is equal to 35.5 g/mol.
2006-11-21 14:42:31 · answer #3 · answered by james matthew a 1 · 0⤊ 0⤋