Rewrite the middle term as the sum of two terms and then factor completely.?

Question

Rewrite the middle term as the sum of two terms and then factor completely. 10x^2 + x - 2

Answer 1

10x^2 + x - 2 = 10x^2 + 5x - 4x - 2
= 5x(2x + 1) -2(2x + 1)
= (5x - 2)(2x + 1)

Answer 2

~ Factor by Grouping ~
ax² + bx + c
(1) Get the grouping number (ac).
(2) Find the factor pair of the grouping number whose sum is equal to (b).
(3) Rewrite the expression using these factors.
(4) Factor by grouping.

10x² + x - 2
(1) 10*-2 = -20 --- Grouping number.
(2) 5 and -4 --- Since (5) + (-4) = 1 --- Factor pair whose sum = b
(3) 10x² + 5x - 4x - 2 --- Rewrite the equation using these factors.
(4) 5x(2x + 1) - 2(2x + 1) --- Take 5x out of 10x² and 5x, and take -2 out of -4x² and -2.

(5x - 2)(2x + 1)

Answer 3

what's they're getting at right this is a thank you to ingredient. be conscious that 15x^2 could be written as 5x circumstances 3x Now what you have chose is to confirm in spite of in case you have 5x-2 circumstances 3x-3 or 5x-thrice 3x-2 they the two provide the spectacular x^2 coeffs, and the spectacular consistent, besides the undeniable fact that it relatively is the x coeff which you're attempting to confirm. in the 1st case above: you get -6-15 = -21 2nd case: -9-10 = -19 so which you would be able to discover which way it is going. This technique gets much less stressful with prepare.

Answer 4

Well, that equation is factorable, so you can just factor it normally.

10x + x - 2

Remember that the last two numbers in the parentheses must add to 1 and multiply to (-2)

(5x - 2)*(2x + 1)

Answer 5

Use that two lines factoring technique....

answer = (5x-2)(2x+1)

Answer 6

+x = 5x-4x
(2x+1)(5x-2)