Factor completely. y^3 - 12y^2 + 36y
2006-11-21 14:23:44 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
OK First you take out the common factor which is y. After you have done that.you have (y^2-12y+36). After this, it becomes simple factoring. The answer is
y(y-6)(y-6)
or also known as y(y-6)^2
2006-11-21 14:26:01 · answer #1 · answered by starrchick101 3 · 0⤊ 0⤋
y^3 - 12y^2 + 36y
Write this as y^3 - 12y^2 + 36y + 0
Let f(y) = y^3 - 12y^2 + 36y + 0
f(0) = 0
So,
y is a factor of p(y)
After synthetic division, we get
p(y) = y(y^2 - 12y + 36)
= y(y - 6)(y - 6)
2006-11-21 14:43:12 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 1⤋
y^3 - 12y^2 + 36y = y*(y^2 - 12y + 36) = y*(y-6)^2
2006-11-21 14:27:52 · answer #3 · answered by James Chan 4 · 0⤊ 0⤋
take out y as a factor...
=y( y^2 - 12y + 36)
= y(y-6)(y-6)
hope u can understand that...
2006-11-21 14:27:53 · answer #4 · answered by Forever happy 3 · 0⤊ 0⤋
y3-12y2+36y y (y2-12y+36) y (y-6) (y-6)* first take out the main suitable ordinary ingredient that's y and you get the expression indexed in line 2, then you relatively ingredient the expression in line 2 and you recieve your answer in line 3.
2016-10-22 12:47:26 · answer #5 · answered by huegel 4 · 0⤊ 0⤋
y(y-6)^2
2006-11-21 18:25:55 · answer #6 · answered by sam 3 · 0⤊ 0⤋
y(y-6)^2
2006-11-21 14:35:42 · answer #7 · answered by Todd D 3 · 0⤊ 0⤋