2x(x-1) / (3) x 4x(x-1) / (1) Would I be able to cross of the (x-1) in this question?

Answer 1

Um, no. Remember when multiplying fractions you multiply across. You can only cancel when you have one in the numerator and one in the denominator with multiplication.

Answer 2

Hmm, well, technically don't you just have 2x(x-1) / 3[4x(x-1)] because it isn't necessary to write that one on the bottom.

Now distribute the 3 in the denomenator:

2x(x-1) / 12x(x-1)

The 2x will divide into the 12x, giving you:

(x-1) / 6(x-1)

Then you see that the (x -1) will divide out, giving you:

1 / 6

Answer 3

nope. the only way you could cross out (x-1) , would be if the equation was
2x(x-1) 1
--------- X --------
3 4x(x-1)

but your equation is:

2x(x-1) 4x(x-1)
--------- X ---------
3 1


the (x-1) has to be in the denominator(on the bottom) and in the numerator(on the top) to be able to cross it out.

(x-1) can't be in both the numerator(on the top) or the denominator(on the bottom).

take care.

Answer 4

No, since only diagonally can you cancel out.

Example:

2x / 52+3y x 52 + 3y / 2x

you cancel out the 2x from the numerator of the first fraction and the denominator of the second fraction

you can also cancel out the 52 + 3y from the denominator of the first fraction and form the numerator of the second fraction

hope i could help

Answer 5

Depends on where you define your parenthesis. It looks like you did not copy accurately.

if you mean
[2x(x-1)/3]*[4x(x-1)/1]
then NO

but if you mean
[2x(x-1)]/[3x4x(x-1)]/1
then YES

Answer 6

The way you have written it, no.