http://online.math.uh.edu/webct/spring06/1310/pt5/images/pt5_f05_problem16__31.gif
I dont know how to solve it :(
2006-11-21 13:08:23 · 4 answers · asked by saira n 1 in Science & Mathematics ➔ Mathematics
Wow, so simple. Thank you!! I'll give you the 10 points as soon as yahoo will let me
2006-11-21 13:15:44 · update #1
log(x + 8) = log(x) + log(8)
According to the laws of logs, log(a) + log(b) = log(ab)
So, log(x) + log(8) = log (8x)
log(x + 8) = log(8x)
The 'logs' cancel each other out.
x + 8 = 8x
x - 8x + 8 = 0
-7x + 8 = 0
-7x = -8
The minus signs cancel each other out
7x = 8
x = 8/7
2006-11-21 13:28:16 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 1⤋
log(x+8)=logx+log8
using 1st Law of log :log(a+b)=logab
log(x+8)=log8x
Find antilog of both sides to remove log
8x=x+8
8x-x=8
7x=8
divide both sides by 7
x=8/7
plug in answer
log(8/7+8)=0.96
2006-11-21 21:45:50 · answer #2 · answered by Phy A 5 · 1⤊ 0⤋
log(x+8)=log(x)+log(8)
log(x+8)=log(x*8)
x+8=8x
x=8/7
you can dro logs in 2nd line because log is always increasing
2006-11-21 21:14:18 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Never mind
2006-11-21 21:39:57 · answer #4 · answered by Anonymous · 0⤊ 1⤋