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V=600m/s
Weight of bullet=5gf
No. of bulletes per min.=250.
Find the POWER

2006-11-21 12:46:19 · 1 answers · asked by SdM 4 in Science & Mathematics Physics

1 answers

Firing the weapon vertically...

V^2 = Vo^2 + 2gh
0 = 600^2 + 2(-9.81)h
h = 18.348 km ; where h is the maximum height reached by the bullet

The work done by firing this bullet to reach the max height is...

W = mgh
W = (5 gf) (9.81 m/s^2) (18.348 km)

BTW, 5 gf? What the fcuk is that? I'll just assume this as 5 grams.

W = 900 N-m or Joules

Power is the rate of doing work. Power therefore is equal to...

P = W x bullets fired per min.
P = 900 x 250 bullets / 60 secs
Power = 3,750 Joules per sec or watts.

2006-11-21 13:51:54 · answer #1 · answered by Askhole Ninja 3 · 0 0

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