apparently, my problems aren`t that hard.
2006-11-21 12:22:44 · 6 answers · asked by jenisebayy 2 in Science & Mathematics ➔ Mathematics
with 4 kids, there are 2^4=16 possible combinations, including the order. Since there's only one way to get all girls p=1/16. For other combinations you have to do some counting since
Two boys and two girls can happen like so:
ggbb
gbgb,
bbgg,
bgbg,
bggb,
gbbg,
note that there are 4 choose 2 = 6 of these. (binomial coeff)
Each of these is 1/16 and there's 6 of them so 6*(1/16) = 6/16.
2006-11-21 12:36:57 · answer #1 · answered by modulo_function 7 · 0⤊ 1⤋
1/16
2006-11-21 12:25:28 · answer #2 · answered by jacinablackbox 4 · 0⤊ 0⤋
Actually, more male children are live births than female. Many things bring down the number of males to closer to the 50/50 ratio in adulthood.
Whatever you have, just be thankful when your children are born healthy.
2006-11-21 12:33:00 · answer #3 · answered by jpbofohio 6 · 0⤊ 0⤋
Mathematically, given the assumption you have stated, the odds are 1 in 16.
Biologically, I believe there are a number of factors that mean that a couple who have already had one girl are more likely to have another girl as their next child.
2006-11-21 12:27:42 · answer #4 · answered by Tim N 5 · 1⤊ 0⤋
if odds are 50/50
all 16 possibilities
GGGG
GGGB
GGBG
GGBB
GBGG
GBGB
GBBG
GBBB
BGGG
BGGB
BGBG
BGBB
BBGG
BBGB
BBBG
BBBB
are equally likely
so answer is 1/16
2006-11-21 12:31:31 · answer #5 · answered by paladin 1 · 0⤊ 0⤋
i think it's 1/6
i'm not 100% sure.....
:P
2006-11-21 12:39:17 · answer #6 · answered by Anonymous · 0⤊ 1⤋