Don't know where to start on this question, thanks in advance
Contestant throwing a 7kg bowling ball straight up in the air. The force exerted in 810N on the ball, the distance of the force exerted is 2m. How high did the ball go from the point of release?
i know to use F=ma as F=(7kg)(9.8) on the ball but don't know which equation to use for the rest of the problem
2006-11-21 11:34:33 · 2 answers · asked by Kevin C 1 in Science & Mathematics ➔ Physics
use conservation of energy:
The 810 N force did work for 2 m
the result is potential energy gained in height working against gravity including the 2m that the 810N force acted on the ball
810*2=7*9.8*(h+2)
h=1620/(7*9.8)-2
=21.6m
j
2006-11-21 12:30:29 · answer #1 · answered by odu83 7 · 1⤊ 0⤋
Simple really what grade you in? I'm in 8th and can do it. F=ma so 810=2m/s(to the second power)*9.8 *m so 810/(2*9.8)=m(mass)
2006-11-21 19:42:00 · answer #2 · answered by Anonymous · 0⤊ 0⤋