how can i solve for x by expressing it in the simplest roots in a+bi formula..
x^2=6x-12
please help. showing the steps is appreciated. thankss
2006-11-21 10:51:29 · 4 answers · asked by BLUEEEE 1 in Business & Finance ➔ Investing
1.) Subtract from both sides(6x -12)
Thus: x^2 - 6x + 12 = 0
2.) Use the quadtric formula to solve
x=-b ±√{b^2 -4ac} / 2a
where:
a = 1
b=-6
c=12
x= 6 ± √{36-48}/2
x= {6 ± √(-12)} /2
Thus remember that i^2 = -1
x= {6 ± √-4 * √3 }/2
x= 3 ± i√3
Final Answer:
3+i√3, 3-i√3
2006-11-21 11:05:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
x^-6x+12
here a=1, b=-6 and c=12
the two roots are -b+/-squ.root of b^2-4ac/22
The roots are
x1=6+(36-48)/2
x2=6+(36+48)/2.
One of the root happens to be complex, ie; because b/a is less than 1. If b/a was greater than one then you will have distinct roots.
2006-11-22 02:43:05 · answer #2 · answered by Mathew C 5 · 0⤊ 0⤋
set every thin g equal to zero (x^2-6x+12 = 0)
use quadratic formula -b +/-square root (b^2 -4ac)//2a
6+-square root 36- 4(1)(12)divided by 2
answer is 3+-i radical3
2006-11-21 18:57:10 · answer #3 · answered by tom33091 2 · 1⤊ 0⤋
I don't know that formula.
But if you need help solving it, take the square root of x^2, and 6x-12. your answer would be
x= +or- 2 square root 6x-3
2006-11-21 18:55:02 · answer #4 · answered by Anonymous · 0⤊ 1⤋