What is X. X=e^(i*pi). ["e" raised to the ("i" times "pi")?

Answer 1

it's -1

e^(ix) = cos x + i*sin x, for real values of x, in radians.

so if x=pi, then this is cos pi which is -1.

Answer 2

The Euler's identity is:

e^(i*n) = cos(n) + i*sen(n)

Switching pi for 'n', you have:

e^(i*pi) = cos(pi) + i*sen(pi) = -1 + i*0 = -1 => e^(i*pi) = -1

Answer 3

-1

Answer 4

As everyone above has stated:

e^(iπ) = -1

In Maths week in New South Wales many years ago a very clever publicity sticker was released that stated:

"Maths teachers are # -e^(iπ)"