A bubble of gas (0.115 cm^3) formed at the bottom of a 12.7 cm deep container of mercury. The temperature is 33 degrees C at the bottom and 33.6 degrees C at the surface, so what is the volume of the bubble just beneath the surface of the mercury in units of cm^3?.
Acceleration of gravity is 9.8 m/s^2. Assume that the surface is at atmospheric pressure 101300 Pa. Use 13600 kg/m^3 as the density of the mercury.
2006-11-21 08:46:51 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Pressure at the bottom = p1 = 12.7 * 0.0136 * 9.8 *10000 + 101300= 118226.56 Pa
T1 at the bottom = 273+33=306 K
T2 at surface = 273+33.6=306.6 K
V1=0.115 cu.cm.
p1*v1/T1 =p2*v2/T2
118226.56 * 0.115 /306 =101300*v2/306.6
we get v2 = 0.1345 cu.cm
2006-11-21 19:41:58 · answer #1 · answered by Harry 3 · 0⤊ 0⤋
0.117cm^3
2006-11-21 17:40:54 · answer #2 · answered by merviedz trespassers 3 · 0⤊ 0⤋