originates from an underwater diver, has a radius of 8 mm at some depth h. When the bubble reaches the surface it has a radius of 9.6 mm. Assume the temperature of the air and the bubble remain constant and that acceleration of gravity is 9.8 m/s^2.
1) Determine the this depth h of the diver in units of m, AND
2) Determine the absolute pressure at depth h in units of Pa.
2006-11-21 08:11:52 · 2 answers · asked by Mariska 2 in Science & Mathematics ➔ Physics
The expansion ratio is 9.8/8 = 1.225, so that is also the pressure ratio compared to 1 atmosphere (101325 Pa)---> P = 101325*1.225 = 124123 Pa
Assuming atmospheric pressure at the surface of the water, the depth to cause the additional .225 atm = .225*10.33m/atm = 2.324 m
Summary:
1) 2.324 m
2) 124123 Pa
2006-11-21 08:30:51 · answer #1 · answered by Steve 7 · 0⤊ 1⤋
Sounds like a job for boyles law if i ever heard one.. dont have time to work on this now, but if you dont get an answer i'll check back
2006-11-21 16:14:40 · answer #2 · answered by Jonny B 5 · 0⤊ 1⤋