2006-11-21 08:01:40 · 15 answers · asked by jaynaee1990 1 in Science & Mathematics ➔ Mathematics
4x + 3y =12, find y = 4
4x+3*4=12
4x+12=12
4x=0
x=0
2006-11-21 08:04:31 · answer #1 · answered by yupchagee 7 · 18⤊ 1⤋
4x + 3(4) = 12
plug 4 in where y is
4x + 12 = 12
subtract 12 from each side
4x = 0
divide by 4
x= 0
2006-11-21 16:30:12 · answer #2 · answered by unan1m0us 5 · 1⤊ 0⤋
Replace y with 4 and solve for x
4x + 3(4) = 12
4x + 12 = 12
Subtract 12 from each side
4x = 0
Divide both sides by 4
x = 0/4 = 0
Answer: x = 0
2006-11-21 16:04:36 · answer #3 · answered by MsMath 7 · 2⤊ 2⤋
4x + 3(4) = 12
4x + 12 = 12 (Subtract 12 from both sides)
4x = 0 (Divide both sides by 4)
x = 0
Check:
4(0) + 3(4) = 12
0 + 12 = 12
12 = 12
QED
2006-11-21 16:14:00 · answer #4 · answered by CSUFGrad2006 5 · 1⤊ 0⤋
Just substitute y =4 in the original equation,
4x + 3(4) = 12
4x = 0
x = 0
2006-11-21 16:05:17 · answer #5 · answered by alrivera_1 4 · 1⤊ 0⤋
4x+3y=12 <---substitute 4 for y
4x+3(4)=12 <--- simplify your equation
4x+12=12 <--- subtract 12 from both sides
4x=0 <-- divide both sides by 4
x= 0
2006-11-21 19:36:00 · answer #6 · answered by Patrick 1 · 1⤊ 0⤋
If you plug y=4 into the equation:
4x+(3*4)=12
4x+12=12
4x=0
x=0
2006-11-21 16:04:58 · answer #7 · answered by banan 2 · 1⤊ 0⤋
4x+3y=12 <---plug in 4 for y to get....
4x+3(4)=12 <--- simplify your equation
4x+12=12 <--- subtract 12 from both sides to get.....
4x=0 <-- divide both sides by 4
x= 0
Now check your answer by plugging both the variables back into the original equation.
4x+3y=12 <---- original equation
4(0)+3(4)=12
0+12=12
12=12 <----- this means that our answer is correct. x=0
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2006-11-21 19:45:16 · answer #8 · answered by Katie 5 · 2⤊ 0⤋
x=0
2006-11-21 16:05:52 · answer #9 · answered by kula o 2 · 1⤊ 0⤋
The problem would be sone as follows:
4x+3(4)=12
4x+12=12
4x=0
x=0
2006-11-21 16:04:49 · answer #10 · answered by Anonymous · 2⤊ 0⤋
4x + 3y =12, find y = 4
4x+(3*4)=12
4x+ 12 =12
4x=0
x=0
2006-11-21 16:17:44 · answer #11 · answered by Anonymous · 1⤊ 0⤋