simplifying algebraic fractions....help please!?

0 ⤊

simplifying algebraic fractions....help please!?

2x+1
_____ + 5/7

3x-4

2006-11-21 07:58:26 · 2 answers · asked by Mark P 1 in Science & Mathematics ➔ Mathematics

2 answers

Multiply (2x+1)/(3x-4) by 7/7 to give 7(2x+1)/7(3x-4)
Multiply 5/7 by (3x-4)/(3x-4) to give 5(3x-4)/7(3x-4)

Now they have a common denominator you can just add the fractions

(7(2x+1) + 5(3x-4))/7(3x-4)

(14x + 7 + 15x -20)/7(3x-4)

(29x - 13)/7(3x-4)

2006-11-21 08:07:29 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋

take lcm
(7(2x+1)+5(3x-4))/7(3x-4)
14x+7+15x-20/7(3x-4)
19x-13/7(3x-4)

2006-11-21 16:05:23 · answer #2 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋