2006-11-21 07:27:52 · 2 answers · asked by Slibuntu 2 in Science & Mathematics ➔ Chemistry
K2(C2O4)*H2O is Potassium oxalate monohydrate. The oxalate is oxidized to CO2 (Carbon dioxide).
KMNO4 is Potassium permanganate. The permanganate is reduced to Mn+2 (Manganese II cation). This requires an acid (H+).
(C2O4)-2 (aq) + (MnO4)-1 (aq) + 8 H+ (aq) --> 2 CO2 (g) + Mn+2 (aq) + 4 H2O (l)
2006-11-21 07:49:47 · answer #1 · answered by Richard 7 · 70⤊ 2⤋
BrO3 - + Sn2+ --> Br- + Sn4+ a million. stability the climate being oxidized/decreased Br in BrO3 - is 5+ and could become a million- as Br-, it positive aspects 6 electrons, decreased Sn2+ will become Sn4+, it loses 2 electrons, oxidized BrO3 - + 6e- --> Br- Sn2+ --> Sn4+ + 2e- 2. stability the oxygens by utilising including H2O to the choice side BrO3 - + 6e- --> Br- + 3H2O Sn2+ --> Sn4+ + 2e- 3. stability the hydrogens by utilising including H+ to the choice side BrO3- + 6H+ + 6e- --> Br- + 3H2O Sn2+ --> Sn4+ + 2e- 4. stability the charges arranged 5. do away with the electrons by utilising multiplying the two equations by utilising a various of a consumer-friendly factor, subsequently 6 BrO3- + 6H+ + 6e- --> Br- + 3H2O 3Sn2+ --> 3Sn4+ + 6e- 6. combine and do away with consumer-friendly components, electrons and compounds BrO3 + 6H+ + 3Sn2+ --> Br- + 3H2O + 3Sn4+
2016-11-25 23:12:45 · answer #2 · answered by ashmore 4 · 0⤊ 0⤋