h.c.f by factorization?

Question

H.CF BY FACTORIZE
H.C.F BY FACTORIZATION

2 3 3 4 2 2
16ab,48ab,80ab

Answer 1

16ab = 2 x 2 x 2 x 2 x a x b
48ab = 2 x 2 x 2 x 2 x 3 x a x b
80ab = 2 x 2 x 2 x 2 x 5 x a x b

Now HCF is the biggest COMMON factor ie biggest factor of them all

So it has 4 2's 1 a and 1 b since each one of these terms have 4 2's, 1 a and 1 b and nothing else in common.

Thus HCF = 2 x 2 x 2 x 2 x a x b = 16ab

I do not understand what you meant by this: 2 3 3 4 2 2

Answer 2

16ab = 2 x 2 x 2 x 2 x a x b
48ab = 2 x 2 x 2 x 2 x 3 x a x b
80ab = 2 x 2 x 2 x 2 x 5 x a x b

Now HCF is the biggest COMMON factor ie biggest factor of them all

So it has 4 2's 1 a and 1 b since each one of these terms have 4 2's, 1 a and 1 b and nothing else in common.

Thus HCF = 2 x 2 x 2 x 2 x a x b = 16ab

I do not understand what you meant by this: 2 3 3 4 2 2

Source(s):

Me ;^))

Answer 3

The greatest common factor of 2, 3, 3, 4, 2, and 2 is 1.

The greatest common factor of 16ab, 48ab, and 80ab is as follows:

16ab = 2 * 2 * 2 * 2 * a * b
48ab = 2 * 2 * 2 * 2 * 3 * a * b
80ab = 2 * 2 * 2 * 2 * 5 * a * b

To find the GCF, "circle" all the numbers that appear in ALL three of the numbers. In this case, you would be circling (in each number) 2 * 2 * 2 * 2 * a * b ... Multiply this to find the GCF:
16ab