Word problems, problem below I`m not getting the right answer?

Question

It costs $1.25 for students and $1.75 for adults to attend a high school basketball game. For a certain game, 323 tickets were sold, which brought in a total $478.75 find out how many of each type of ticket were sold

Answer 1

S + A = 323
1.25S + 1.75A = 478.75

1.25(323 - A) + 1.75A = 478.75
403.75 + 0.5A = 478.75
A = 150, S = 173

Answer 2

One way to do this is by setting up a system of equations.

Let S = student price. Let A = adult price.

S + A = 323 [tickets sold]
1.25S + 1.75A = $478.75 [money brought in]

I'll multiply the second line by 4. (I don't like working with decimals.)

S + A = 323
5S + 7A = 1915. [Multiply the top line by -5 to eliminate S.]

-5S - 5A = -1615
5S + 7A = 1915. [Add both rows.]

2A = 300
A = 150.

S + A = 323
S + (150) = 323
S = 173.

There were 173 student tickets and 150 adult tickets sold.

Answer 3

This is a two variable, two equation problem:

s = # of students who attended
a = # of adults who attended

s + a = 323
1.25s + 1.75a = 478.75

You can use a substitution method to solve for one of the variables.

Since s + a = 323, then a = 323 - s. Plug that into the second equation and you get:
1.25s + 1.75(323 - s) = 478.75

1.25s + 565.25 - 1.75s = 478.75
-.5s = -86.5
thus s = 173
thus a = 150

Answer 4

Let

x = students tickets

y = adults Tickets

323 = total tickets

1.25x = cost of students tickets

1.75 = cost of adult tickets

478.75 = Total cost of all tickes

- - - - - - - - - - -

x + y = 323 - - - - - - - - - - - -Equation 1
1.25x = 1.75y = 478.75- - - -Equation 2
- - - - - - - - - - - - - - - -

Substitute Method equation 1

x + y = 323

x + y - x = 323 - x

y = 323 - x

Insert the y value into equation 2

- - - - - - - - - - - - - - - - - - - - - -

Solving for x

1.25x + 1.75y = 478.75

1.25x + 1.75(323 - x) = 478.75

1.25x + 565.25 - 1.75x = 478.75

- .5x + 565.25 = 487.75

- .5x+ 565.25 - 565.25 = 478.75 - 565.25

-.5x = - 86.5

- .5x/- .5 = - 86.5/ - .5

x = 173

The answeris x = 173

Insert the x value into equation 1

- - - - - - - - - - - - - - - - - - - - - -

Solving for y

x + y = 323

173 + y = 323

173 + y - 173 = 323 - 173

y = 150

The answer is y = 150

Insert the y value into equation 1

- - - - - - - - - - - - - - - - - - - - - -

Check for equation 1

x + y = 323

173 + 150 = 323

323 = 323

- - - - - - - - - - - -

Check for equation 2

1.25x + 1.75y = 478.75

1.25(173) + 1.75(150) = 478.75

216.25 + 262.50 = 478.75

478.75 = 478.75

- - - - - - - - - - - - -

There was 173 student tickes sold. $ 216.25

There was 150 adult tickets sold $ 262.50

- - - - - - s-

Answer 5

Set up a chart to organize your data (This is going to look like crap because I'm using a proportional font)....

Cost # of tickets Total cost
Students 1.25 x 1.25x
Adults 1.75 y 1.75y
-------------------------------------------------------
Total 323 478.75

Set up a system of equations

x+y=323
1.25x+1.75y=478.75

(Can use either the addition method or the substitution method. I'm going with the latter here, out of convenience...)

x+y=323
x = 323-y

1.25(323-y) + 1.75y = 478.75
403.75 - 1.25y + 1.75y = 478.75
0.5y = 75
y = 150

Since y = 150....
x+150=323
x=173

173 student tickets, 150 adult tickets.

Answer 6

Let x = the number of student tickets
323-x = number of adult tickets
So 1.25x + 1.75(323-x) = 478.75
1.25 x +1.75*323 -1.75x =478.75
-.5 x = 478.75- 1.75*323= -86.5
x = 2(86.5)= 173 = # of students
323 -173=150 = # of adults

Answer 7

A = 150, S = 173

Answer 8

set up a system of equations
x = student
y = adult

1.25x + 1.75y = 478.75
x + y = 323

1.25x + 1.75y = 478.75
(x + y = 323)(-1.25)

1.25x + 1.75y = 478.75
-1.25x - 1.25y = -403.75

add the two equations together

.50y = 75
y = 150

plug y back into one of the equations
x + y = 323
x + 150 = 323
x = 173

ANSWER
x = 173
y = 150

Answer 9

# of student tickets =a
# of adult tickets =b

1.25a + 1.75b=478.75

a+b=323

therefore:

b=323-a substitute for b in the first equation

1.25a+1.75(323-a)=478.75

solve for a then substitute in either equation and solve for b.

1.25a + 565.25 - 1.75a=478.75
-.5a+565.25=478.75
-.5a=-86.5
a=173
b=150

Answer 10

a + s = 323
a = 323-s

1.25*s + 1.75*a = 478.75
1.25*s + 1.75*(323-s) = 478.75
-0.5s + 565.25 = 478.75
s = 173

a = 323-s
a = 323-173
a = 150