Universe question?

Question

If anyone could help me out with this, it would be great! Thank you!
Suppose a spaceship is moving at 0.993c. How many times slower does the spaceship's clock appear to be running than a "stationary" clock? I have to use the Lorentz factor somehow...

The answer has to be greater than one.

That's what I thought too. There doesn't seem like there is enough information in the problem to try to get to the answer. :(

Thank you to everyone! :)

Answer 1

root{1 - (v/c)^2} = root{1 - 0.993^2} = 0,118
This is the wished factor

Th

Answer 2

The formula is T=T(o) sqroot (1-v*v/c*c). The stuff in parenthesis should be 1 - v squared divided by c squared. Sorry, but the computer won't let me enter mathematical equations.

T is the total time to the mover
T(o) is the total time according to the observer ("outside")
v = velocity
c = speed of light

Let c(sq) = c * c, or c squared

Since you give .993c as your speed, you get .993c(sq)/c(sq), or about .996. All you are concerned is a ratio, the comparison of the speed with the speed of light, then square the answer.

Your formula should now read:
T=T(o) sqroot (1-.996), subtract to get
T=T(o) sqroot (.0035),
T=T(o) .05921

You aren't given a time, so you could use, say T(o) = 1 hour,
which means the time "felt" by the one in motion = .05921 hours, or a little over 3.55 minutes. Hope this helps.

Answer 3

Thermo's answer is correct.

If you want to know how many times slower, then just divide
1/0.118 = 8.47 times slower

Answer 4

http://www.thebigview.com/spacetime/timedilation.html

I get the same answer as the guy below me, but I'm still not sure how to replace T. It's too vague.

0.993c is 99.3% of the speed of light.

Answer 5

im doin a phsyics degree and i dont know what ur on about ;p

Answer 6

I appologize for my stupidity. I do not know what 0.993c is.