2006-11-21 06:47:45 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x+3)(x-1)
x= -3
x=1
2006-11-21 06:50:05 · answer #1 · answered by veryintrigued 2 · 1⤊ 3⤋
x= -3 and 1
2006-11-21 06:51:04 · answer #2 · answered by Dan 2 · 0⤊ 0⤋
Well I wouldn't mind getting a couple of points here, if for no other reason than to point out to you that this is not a question even if you did put a question mark at the end of your statement.
x^2+2x-3 is a polynomial for which you can ask a lot of questions.
It's a second degree polynomial.
It's a trinomial.
It could be the equation of a parabola if you set it equal to something.
It's factorable. (which turns into (x - 1)(x + 3) in factored form)
But for those people who keep telling you that x = 1 and x = -3, they are sadly wrong. Unless of course the question that you did not ask was "What are the values of x that make this polynomial equal to zero?"
So now I have my two points, you have an idea that you should really ask questions and not make statements to which people are supposed to respond, and now I wish you a very good day. :)
2006-11-21 07:03:38 · answer #3 · answered by SmileyGirl 4 · 0⤊ 1⤋
x^2 + 2x - 3
(x - 1)(x + 3)
x = 1, -3
2006-11-21 06:54:41 · answer #4 · answered by trackstarr59 3 · 0⤊ 0⤋
so far it looks like the factors are correct that others have given. it is (x+3)(x-1) which means that x= -3 and x= 1. You have to make sure you solve for x (set each part equal to zero: x+3=0)
2006-11-21 06:54:35 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x+3)(x-1)
2006-11-21 06:51:16 · answer #6 · answered by raj 7 · 0⤊ 0⤋
You can't award just 3 points for best answer. Best answer gets 10 points. This has no answer anyway. It is not an equation. You must specify what you want. It appears to be a factoring problem or you have forgotten to add "=0" to the equation. Either way, you wasted 5 points for nothing.
2006-11-21 06:52:29 · answer #7 · answered by Anonymous · 1⤊ 0⤋
x^2+2x-3
(x-1)(x+3)
x=1 and -3
2006-11-21 06:52:03 · answer #8 · answered by 7 · 0⤊ 0⤋
x^2 + 2x - 3 = 0
(x + 3)(x - 1) = 0
x + 3 = 0 or x - 1 = 0
x = -3 or x = 1
QED
2006-11-21 08:18:55 · answer #9 · answered by CSUFGrad2006 5 · 0⤊ 0⤋
x^2 + 2x - 3 = (x+3)(x-1)
If you wish to know yhe values of x that make the above expression = 0, then:
x+3=0
x=-3
X-1 =0
x=1
2006-11-21 06:53:04 · answer #10 · answered by ironduke8159 7 · 0⤊ 0⤋
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2016-11-25 23:07:57 · answer #11 · answered by brim 4 · 0⤊ 0⤋