3a + 5b =1- - - - - -Equation 1
4a + 2b = 6- - - - - Equation 2
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Multiply equatio 1 by - 1 and equation 2 by 5
3a + 5b = 1
- 2 (3a) + - 2(5b) = - 2(1)
- 6a + (-10b)= - 2
- 6a - 10b = - 2. . .New equation 1
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4a + 2b = 6
5(4a) + 5(2b) = 5(6)
20x + 10b = 30. . . New equation 2
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New equation 1 and new equation 2
Elimination of b, Solving for a
-6a - 10b = - 2
20a + 10b = 30
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14a = 28
14a/14 = 28/14
a = 2
The answer is a = 2
Insert the a value into equation 1
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Solving for b
3a + 5b = 1
3(2) + 5b = 1
6 + 5b = 1
6 + 5b - 6 = 1 - 6
5b = -5
5b/5= - 5/5
b = - 1
The answer is b = - 1
Inserty the b value into equation 1
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Check for equation 1
3a + 5b = 1
3(2) + 5(- 1) = 1
6 + (-5) = 1
6 - 5 = 1
1 = 1
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Check for equation 2
4a + 2b = 6
4(2) + 2(- 1) = 6
8 + (- 2) = 6
8 - 2 = 6
6 = 6
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The solution set { a, b ]
The solution set is { 2, - 1 }
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2006-11-21 12:17:12
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answer #1
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answered by SAMUEL D 7
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ab + 3a + 2b +6 the 1st term is ab as a bring about the bracketed factorization the 1st ingredient is a * b (a + ?) (b + ?) The final term in the unique function is 6 which could be factored as a million * 6 or 2 * 3 As there's a 3a and a 2b in the unique function then the climate of 6 are 2 * 3 and as there must be 3a the three ought to be in the (b + ?) area of the factorization So the climate are (a +2)(b +3)
2016-10-22 12:11:47
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answer #2
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answered by ? 4
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3a + 5b = 1
4a + 2b = 6
4(3a) + 4(5b) = 4(1)
3(4a) + 3(2b) = 3(6)
12a + 20b = 4
12a + 6b = 18
12a + 20b = 4
-1(12a) + -1(6b) = -1(18)
12a + 20b = 4
-12a - 6b = -18
12a - 12a + 20b - 6b = 4 -18
14b = -14
b = -1
By substituting -1 for b we get: 3a + 5(-1) = 1
3a + -5 = 1
3a = 1 + 5
3a = 6
a = 3
Thus a = 3 and b = -1
I hope the explanation helps.
2006-11-21 06:55:22
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answer #3
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answered by Denny 3
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3a+5b=1 multiply by -4
-12a-20b=-4
4a+2b=6 multiply by 3
12a+6b=18
-12a-20b=-4 add
-14b=14 divide by -14
b=-1
substitute
3a+-5=1 add 5
3a=6 divide by 3
a=2
solution is (2,-1)
check
4*2+2*-1=6
8-2=6
2006-11-21 08:42:48
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answer #4
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answered by yupchagee 7
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3a+5b=1
3a=1-5b
a=(1-5b)/3
substitute for "a" in the other equation and solve for "b"
4((1-5b)/3)+2b=6
b=2
a=-1
2006-11-21 06:56:57
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answer #5
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answered by Rorshach4u 3
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-4(3a+5b=1)
3(4a+2b=6)
=========
-12a-20b=-4
12a+6b=18
=========
-14b=14
b=-1
3a+5(-1)=1
3a-5=1
3a=6
a=2
(2,-1)
Check:
3(2)+5(-1)=1
6-5=1
1=1
4(2)+2(-1)=6
8-2=6
6=6
2006-11-21 07:58:01
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answer #6
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answered by Anonymous
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12a+20b=4
-12a-6b=-18
adding
14b=-14
b=-1
sub
3a-5=1
3a=6
a=6/3=2
a=2,b=-1
2006-11-21 06:50:30
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answer #7
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answered by raj 7
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