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solve by elimination

2006-11-21 06:45:16 · 7 answers · asked by brentvestby2000 1 in Science & Mathematics Mathematics

7 answers

3a + 5b =1- - - - - -Equation 1
4a + 2b = 6- - - - - Equation 2
- - - - - - - - - -

Multiply equatio 1 by - 1 and equation 2 by 5

3a + 5b = 1
- 2 (3a) + - 2(5b) = - 2(1)

- 6a + (-10b)= - 2

- 6a - 10b = - 2. . .New equation 1

- - - - - -- - - - - -
4a + 2b = 6

5(4a) + 5(2b) = 5(6)

20x + 10b = 30. . . New equation 2

- - - - - - - - - - - -

New equation 1 and new equation 2

Elimination of b, Solving for a

-6a - 10b = - 2
20a + 10b = 30
- - - - - - - - - - - -
14a = 28

14a/14 = 28/14

a = 2

The answer is a = 2

Insert the a value into equation 1

- - - - - - - - - - - - - - - - - - - - - -

Solving for b

3a + 5b = 1

3(2) + 5b = 1

6 + 5b = 1

6 + 5b - 6 = 1 - 6

5b = -5

5b/5= - 5/5

b = - 1

The answer is b = - 1

Inserty the b value into equation 1

- - - - - - - - - - - - - - - - - - - - - - -

Check for equation 1

3a + 5b = 1

3(2) + 5(- 1) = 1

6 + (-5) = 1

6 - 5 = 1

1 = 1

- - - - - - - - - - - - -

Check for equation 2

4a + 2b = 6

4(2) + 2(- 1) = 6

8 + (- 2) = 6

8 - 2 = 6

6 = 6

- - - - - - - - - - - -

The solution set { a, b ]

The solution set is { 2, - 1 }

- - - - -s-

2006-11-21 12:17:12 · answer #1 · answered by SAMUEL D 7 · 2 0

ab + 3a + 2b +6 the 1st term is ab as a bring about the bracketed factorization the 1st ingredient is a * b (a + ?) (b + ?) The final term in the unique function is 6 which could be factored as a million * 6 or 2 * 3 As there's a 3a and a 2b in the unique function then the climate of 6 are 2 * 3 and as there must be 3a the three ought to be in the (b + ?) area of the factorization So the climate are (a +2)(b +3)

2016-10-22 12:11:47 · answer #2 · answered by ? 4 · 0 0

3a + 5b = 1
4a + 2b = 6

4(3a) + 4(5b) = 4(1)
3(4a) + 3(2b) = 3(6)

12a + 20b = 4
12a + 6b = 18

12a + 20b = 4
-1(12a) + -1(6b) = -1(18)

12a + 20b = 4
-12a - 6b = -18

12a - 12a + 20b - 6b = 4 -18
14b = -14
b = -1

By substituting -1 for b we get: 3a + 5(-1) = 1
3a + -5 = 1
3a = 1 + 5
3a = 6
a = 3

Thus a = 3 and b = -1

I hope the explanation helps.

2006-11-21 06:55:22 · answer #3 · answered by Denny 3 · 0 2

3a+5b=1 multiply by -4
-12a-20b=-4
4a+2b=6 multiply by 3
12a+6b=18
-12a-20b=-4 add
-14b=14 divide by -14
b=-1
substitute
3a+-5=1 add 5
3a=6 divide by 3
a=2
solution is (2,-1)
check
4*2+2*-1=6
8-2=6

2006-11-21 08:42:48 · answer #4 · answered by yupchagee 7 · 2 0

3a+5b=1
3a=1-5b
a=(1-5b)/3

substitute for "a" in the other equation and solve for "b"
4((1-5b)/3)+2b=6

b=2
a=-1

2006-11-21 06:56:57 · answer #5 · answered by Rorshach4u 3 · 1 0

-4(3a+5b=1)
3(4a+2b=6)
=========
-12a-20b=-4
12a+6b=18
=========
-14b=14
b=-1
3a+5(-1)=1
3a-5=1
3a=6
a=2
(2,-1)

Check:
3(2)+5(-1)=1
6-5=1
1=1

4(2)+2(-1)=6
8-2=6
6=6

2006-11-21 07:58:01 · answer #6 · answered by Anonymous · 1 0

12a+20b=4
-12a-6b=-18
adding
14b=-14
b=-1
sub
3a-5=1
3a=6
a=6/3=2
a=2,b=-1

2006-11-21 06:50:30 · answer #7 · answered by raj 7 · 2 0

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