Physics. Where is my mistake? 2 Oscillation problems. Home work. A meter stick is suspended at one end?

Question

A meter stick suspended at one end by a .365 m long light string, is set into oscillation. The acc. of gravity is 9.8 m/s^2. Determine the period of oscillation. Answer in units of s.
My INCORRECT solution:
L=1.365
g=9.8 m/s^2
T=2pi(^2root L/g)
T=2pi (^2 root 1.365/9.8)
T=2pi (^2root .1392857143)
T=2pi (.3732100136)
T=2.344947674 This is incorrect!!!

Problem #2
At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 24.9786 cm on a spring with a apring constant of 15.4144 N/m. The mass of the bananas is 41.4019 kg. What is the speed of the bananas? Answer in units of m/s.
My INCORRECT solution:
w= ^2 root (k/m)
24.9786 cm = .249786 m amplitude
15.4144 N/m spring constant
41.4019 kg mass
w=^2 root 15.4144 N/m / 41.4109 kg
w=^2 root .3723114
w=.6101732 This is incorrect!!!
Any and all help is appreciated. I would like to see it worked out.

Answer 1

First problem: You have assumed all the mass of the meter stick is concentrated at the lower end; obviously, it is uniformly distributed along the length of the stick. Assume that the mass is concentrated at the center; then, the length of the oscillator will be 0.865 meters, and the period should correspond. There are some complications involving moment of inertia which I am ignoring.
Second problem: You may be solving for the wrong thing. It looks like you are solving for the frequency of oscillation, rather than the maximum speed of motion. Some careful work with units will help show you what is going on.

Answer 2

Problem #1

It is not a simple pendulum but compound pendulum. The correct formula for T is

T = 2pi*sqrt[(l+k*k/l)/g], here k is radius of gyration of meter scale about cenre of gravity and l is the length from point of suspension to centre of gravity

so l = .865 m and k = sqrt(1/12) = 1/[2sqrt(3)]

substitute and recalculate

problem #2

PE = KE
(1/2)kx*x = (1/2)mv*v

v = sqrt (k/m)*x

v = .621*.24 = .15 m/s