Solve: 2x + 1 = 5x/3
Please show steps
2006-11-21 05:24:41 · 4 answers · asked by mbchelsea 1 in Science & Mathematics ➔ Mathematics
2x + 1 = 5x/3
6x + 3 = 5x
1x + 3 = 0
1x = -3
x = -3
2006-11-21 05:27:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Hmm-m-m, not to hard a problem...
2X + 1 = 5X / 3
Multiply both sides by 3 to get rid of that fraction on the right side.
6X + 3 = 5X
Transpose the 5X to the other side of the equal sign making it negative...
6X - 5X + 3 = 0
Now, transpose the +3 to the other side of the equal sign...
that also makes it negative...
So
6X - 5X = -3
and
X = - 3
Zahbudar
2006-11-21 13:47:00 · answer #2 · answered by zahbudar 6 · 0⤊ 0⤋
2x+1=5x/3
multiply both sides by 3
6x+3=5x
x=-3
have not had algebra in fifty years but thats my guess
2006-11-21 13:39:38 · answer #3 · answered by rallman@sbcglobal.net 5 · 0⤊ 0⤋
2x+1=5x/3
6x+3=5x
3=-x
x=-3
2006-11-21 13:30:09 · answer #4 · answered by pito16places 3 · 0⤊ 0⤋