Extreme position!
Because acceleration is directly propotional to the displacement from the mean position and directed opposite to it.
a=-(ω^2)x
2006-11-24 05:21:09
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answer #1
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answered by Anonymous
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The correct answer is the extreme position. The question was regarding acceleration. Velocity is greatest at the mean position.
2006-11-21 03:26:24
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answer #2
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answered by Paul B 1
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Acceleration is maximum at extreme position. It is Maximum equal and opposite, at each extreme points.
Both positions are maxima and the minima but for different vectors.
Take ball hanging from the string.
It is at rest in the centre.
Pull it away in one direction and release it.
Velocity at this point is Zero to start with.
Acceleration due to gravity takes over this is max acceleration at the point of release.
Because of this acceleration velocity becomes max at the centre. It start changing the direction start to slow down acceleration is now also in the opposite direction, reaches the top, velocity goes to zero, actually stops there, start free falling, because of acceleration of gravity,undertake reverse process.......
So acceleration is maximum at extreme position. It is Maximum equal and opposite, at each extreme points.
2006-11-21 06:16:44
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answer #3
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answered by minootoo 7
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Mean position.
The speed is zero at the extreme position.
2006-11-21 03:13:25
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answer #4
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answered by Wil T 3
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At mean position.
2006-11-21 03:21:07
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answer #5
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answered by Paritosh Vasava 3
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Extreme position is the correct answer. Example the pendulum
2006-11-21 03:13:30
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answer #6
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answered by Anonymous
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accelaration is maximum at d extreme position because d body wnts 2 come bck to its mean or original position
2006-11-24 04:20:04
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answer #7
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answered by mundane gal 2
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extreme position
a = A(w^2)sin(wt)
this is maximum at the extreme position
while velocity is max at mean position
2006-11-21 03:45:10
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answer #8
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answered by sandy 1
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1)d. The force exerted on the particle is proportional to its displacement but has the opposite sign. 2)By T = 2π√[L/g] =>T = 2 x 3.14 x √[1/23.12] =>T = 1.30 sec =>(a) 3)c. Its velocity is zero at the equilibrium position.
2016-05-22 07:10:33
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answer #9
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answered by Anonymous
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The acceleration is max at its extreme position.
a= omega square * x
omega is max at extreme position. so acceleration is max at that position.
2006-11-21 23:07:44
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answer #10
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answered by scholar 2
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